A coordination number can be determined by the usage of an atom towards a molecule from seeing how many numbers of atoms would have to be combined together in an atom.
B. Mn + NiBr₂ → Ni + MnBr₂
Explanation:
The reaction that can be predicted of all is Mn + NiBr₂ → Ni + MnBr₂.
The activity series is used to predict the products of single displacement reactions.
The series ranks metals in order of their reactivity. Those higher up in the series are highly reactive metals. Those at the bottom are slightly to non-reactive metals.
For a single displacement reaction to occur, a metal higher up in the activity series displaces one that is lower in the series.
Reaction A will not occur, Ba is higher in the series
Reaction C will not occur, Pt and Au are unreactive
Reaction D will not occur as Zn is lower in the series
Mn is higher in the reactivity series and it will displace Ni from the solution.
Learn more:
Synthesis reaction brainly.com/question/4216541
#learnwithBrainly
Answer: left
Explanation: The element that appears farthest to the
✔ left
is written first in the chemical name of a covalent compound.
Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the molality of the given solution, we need to convert the mass of solute into moles and divide it to the mass of the solvent.
Molality = 29.5 g glucose (1 mol / 180.16 g ) / .950 kg water
Molality = 0.1724 mol / kg
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
= 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
=0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
= 0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16)
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2
∴ the emprical formula C3H8O2