For this problem, we use the equation derived from Beer's Law as written below:
A = ∈LC,
where
A is the absorbance
∈ is the molar absorptivity
L is the path length of the cuvette
C is the concentration of the sample solution placed in the cuvette
To determine C, we have to know the rest of the parameters. Generally, the equation for C would be:
C = A/∈L = A/∈(1 cm)
C = A/∈
If you know the absorbance and the molar absorptivity in mol/L·cm, you can determine the value of C.
<span>To
solve this we assume that the gas is an ideal gas. Then, we can use the ideal
gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another
set of condition of temperature, the constant is still the same. Calculations
are as follows:</span>
P1V1/T1 = P2V2/T2
P1 = P2V2T1/T2V1
P1 = (114)(1.32)(596)/(715)(.654)
P1 = 191.80 kPa
Answer:5.309 × 10²⁴ atoms.
Explanation:
Given that
molar mass of NH3 = 17
g/mol
Mass of NH3 = 5g
Therefore, No of moles of NH3 = Mass/ molar mass
= 5g/ 17g/mol
= 0.294 moles.
I mole = 6.02 × 10²³ atoms
Therefore the number of hydrogen atoms in a 0.294 moles of ammonia gives us
0.294× 6.02 × 10²³ × 3 ( since there are 3 hydrogens in Ammonia )
= 5.309 × 10²⁴ atoms.
Explanation:
The formula mass of a molecule (also known as formula weight) is the sum of the atomic weights of the atoms in the empirical formula of the compound.
a. NO2
N = 14
O = 16
NO2 = 14 + (16 * 2) = 46 amu
b. C4H10
Empirical formular = C2H5
C = 12
H = 1
C2H5 = (12*1) + (1*5) = 12 + 5 = 17 amu
c. C6H12O6
Empirical formular = CH2O
C = 12
H = 1
O = 16
C2H5 = 12 + (1*2) + 16 = 30 amu
d MgBr2
Mg = 24
Br = 80
MgBr2 = 24 + (80*2) = 184 amu
e. HNO2
H = 1
N= 14
0 = 16
HNO2 = 1 + 14 + (16*2) = 47 amu
f. CBr4
C= 12
Br = 80
CBr4 = 12 + (80*4) = 332 amu
g. Cr(NO3)3
Cr = 52
N = 14
O = 16
Cr(NO3)3 = 52 + 3[14 + (3*16)] = 238 amu
The kinetic theory states that matter consists of particles in constant motion.
