Consider the elements in the periodic table. The stair-step line between the pink squares and the yellow squares separates the _
1 answer:
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Answer:
The correct answer is - option C.
Explanation:
Given: the melting point of HCl is
-114.8 °C, which suggests that below this temperature HCl will be solid.
and, since the boiling point of HCl is - 85.1 °C. It is also suggested that above this temperature HCl will be gas, Therefore.
Solid -114.8 - Ordered arrangement
Liquid -85.1c - Less orderly arranged
Gaseous - Least orderly arranged
Thus, at —90 °C, HCl will be present 'in the liquid state, At — 1 °C, HCl will be present in the gaseous state and at -129 °C, HCl will be present in the solid-state. So, the molecules will be organized in a more orderly manner .
Thus, the correct answer is - option C
Answer:
1. Diastereomers have different physical properties (unlike most aspects of enantiomers) and often different chemical reactivity. ... Many conformational isomers are diastereomers as well. Diastereoselectivity is the preference for the formation of one or more than one diastereomer over the other in an organic reaction.
2. The result is a trans dibromide, as shown in the equation below
Explanation:
Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer.[1] Diasteoreomers are defined as non-mirror image non-identical stereoisomers. Hence, they occur when two or more stereoisomers of a compound have different configurations at one or more (but not all) of the equivalent (related) stereocenters and are not mirror images of each other.[2] When two diastereoisomers differ from each other at only one stereocenter they are epimers. Each stereocenter gives rise to two different configurations and thus typically increases the number of stereoisomers by a factor of two.
2. the addition of bromine to the trans and
cis isomers of 1,2-diphenylethene, more commonly known as trans- and cis-stilbene.
H
H
H H
trans-stilbene cis-stilbene
m.p. 122-124°C b.p. 82-84°C
density 0.970 g/mL density 1.011 g/mL
M.W. 180.25 g/mol M.W. 180.25 g/mol
In both cases, the nucleophilic double bond undergoes an electrophilic addition reaction
by the bromine reagent which proceeds via a cyclic bromonium ion. The addition of
bromine begins at one side of the double bond (either side is equally likely, but only one
option is drawn) and is followed by attack of bromide ion on the bromonium ion (again,
attack could occur at either carbon since the ion is symmetric, but only one option is
drawn). The result is a trans dibromide, as shown in the equation below:
Since the cis and trans isomers of stilbene have different geometries, it follows
that upon reaction with bromine they give rise to stereoisomeric bromonium ions and,
eventually, products that differ only by their stereochemistry.
