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2 years ago

Consider the reaction below. 2al2o3 → 4al 3o2 what is the mole ratio of oxygen to aluminum? o2:al = :4

Chemistry

1 answer:

charle [14.2K]2 years ago

3 0

Answer:

3/4

Explanation:

2Al2O3 → 4Al + 3O2

Molar ratio of oxygen to aluminum is 3/4.

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An unknown solid acid is either citric acid or tartaric acid. To determine which acid you have, you titrate a sample of the soli

Norma-Jean [14]

Answer:

The unknown acid is citric acid.

Explanation:

Based on the reactions:

Citric acid: H3C6H5O7(aq) + 3NaOH (aq) → 3H2O (l) + Na2C6H5O7 (aq)

Tartaric acid: H2C4H4O6 (aq) + 2NaOH (aq) → 2H2O (l) + Na2C4H4O6 (aq)

0.956g of sample if tartaric acid requires:

0.956g × (1mol / 150,087 g) = 0.006370 moles of tartaric acid. As 1 mole reacts with 2 moles of NaOH:

0.006370 moles of tartaric acid × (2 mol NaOH / 1 moles tartaric acid) = 0.0127 moles of NaOH. As the concentration of the NaOH is 0.513M:

0.0127 moles of NaOH × (1L / 0.513mol) = 0.0248L ≡ 24.8mL

Now, 0.956g of citric acid requires:

0.956g × (1mol / 192,124g) = 0.004976 moles of citric acid. As 1 mole reacts with 3 moles of NaOH:

0.004976 moles of citric acid × (3 mol NaOH / 1 moles tartaric acid) = 0.0149 moles of NaOH. As the concentration of the NaOH is 0.513M:

0.0149 moles of NaOH × (1L / 0.513mol) = 0.0291L ≡ 29.1mL

As the titration requires 29.1mL of the base, the unknown acid is citric acid.

5 0

3 years ago

Read 2 more answers

Identify each definition that applies to the compound in red Check all that apply Mg(OH) 2 +H 2 SO 4 2H 2 O+MgSO 4

vichka [17]

Answer:

Arrhenius Base

Bronsted-Lowry Base

Explanation:

4 0

4 years ago

Read 2 more answers

A BaSO4 slurry is ingested before the gastrointestinal tract is x-rayed because it is opaque to x-rays and defines the contours

NNADVOKAT [17]

Explanation:

The given reaction equation is as follows.

$BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO_{4}^{2-}(aq)$

The value of $\Delta G^{o}$ = 59.1 kJ/mol

We know that ,

$\Delta G^{o} = -RT ln K_{sp}$

or, $ln K_{sp} = -(\frac{\Delta G^{o}}{RT})
$

= -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]

= -22.93

or, $K_{sp} = e^{-22.93}$

= $1.1 \times 10^{-10}$

$K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]$

Therefore, $[Ba^{2+}] =\sqrt{K_{sp}}$

= $\sqrt{ 1.1 \times 10^{-10}}$

= $1.05 \times 10^{-5} M$

Therefore, we can conclude that the value of $[Ba^{2+}]$ in the intestinal tract is $1.05 \times 10^{-5} M$ .

7 0

3 years ago

Which two electron configurations represent elements that would have similar chemical properties? (1) 1s22s22p4 (2) 1s22s22p5 (3

Anton [14]

Answer: Two electron configurations of elements that would have similar chemical properties are (2) and (4).

Explanation:

(1) $1s^22s^22p^4$

(2) $1s^22s^22p^5$

(3) $[Ar]4s^23d^5$

(4) $[Ar]4s^23d^{10}^4p^5$

Valence electrons : These are the electrons present in last principal quantum number of an atom of the element.

Two electron configurations represent elements that would have similar chemical properties are (2) and (4). This is because number of valence electrons present in both of them are same that is seven valence electrons . Also valence electrons of both the elements are present in p-orbital which means that they both belongs to same group in a periodic table. The members of same group in a periodic table have similar chemical properties.

3 0

3 years ago

Which of the following is true about the law of consevation

Mkey [24]

Answer:

just look it up

Explanation:

4 0

3 years ago