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Arlecino [84]
2 years ago
11

Consider the reaction below. 2al2o3 → 4al 3o2 what is the mole ratio of oxygen to aluminum? o2:al = :4

Chemistry
1 answer:
charle [14.2K]2 years ago
3 0

Answer:

3/4

Explanation:

2Al2O3 → 4Al + 3O2

Molar ratio of oxygen to aluminum is 3/4.

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In the oxidation reduction reaction 2FeCl2 + Cl2 = 2FeCl3 what substance is reduced? What substance is oxidized?
marishachu [46]

Answer:

Iron is oxidized while chlorine is reduced.

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reaction:

2FeCl₂  + Cl₂  →  2FeCl₃

in this reaction the oxidation state of iron is increased from +2 to +3. That's why iron get oxidized and it is reducing agent because it reduced the chlorine. The chlorine is reduced from -2 to -3 and it is oxidizing agent because it oxidized the iron.

2Fe⁺²Cl₂⁻²

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The iron atom gives it three electrons to three atoms of chlorine and gain positive charge while chlorine atom accept the electron and form anion.

4 0
3 years ago
6) A volume of 473 mL of oxygen was collected at 27°C. What volume would the oxygen occupy at
sertanlavr [38]

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K

Now put all the given values in above equation, we get:

\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

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Explanation:

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