The relative frequency distribution of the number of phobias reported by a hypothetical sample of 500 college students is given as follows. 0–2 0.48
3–5 0.26
6–8 0.12
9–11 0.09
12–14 0.05
Required:
a. What is the probability that a college student expresses fewer than three phobias?
b. What is the probability that a college student expresses more than eight phobias?
c. What is the probability that a college student has between 3 and 11 phobias?
1 answer:
Answer:
a. 0.48
b. 0.14
c. 0.47
Step-by-step explanation:
Data provided in the question
0 - 2 0.48
3 - 5 0.26
6 - 8 0.12
9- 11 0.09
12- 14 0.05
Based on the above information
a. The probability for fewer than three phobias is
= P( x < 3)
= 0.48
b. The probability for more than eight phobias is
= P( x >8)
= 0.09 + 0.05
= 0.14
c. Probability between 3 and 11 phobias is
= P(3 < x < 11)
= 0.26 + 0.12 + 0.09
= 0.47
You might be interested in
To find the mean add up all the numbers and divide. The mean absolute deviation is the difference.
Answer:
YES
Step-by-step explanation:
cause 12.6 / 4.5 = 2.8
and 4.2 / 1.5 = 2.8
Answer:
11 boxes will be fully packed and .25 will be remaining
Answer:
946 sq inches
Step-by-step explanation:
28*7=196
30*25=750
750+196=946 i think thats how you do it lol
(=^w^=)
The only thing you need to do is to plug in x to get y.hope this helps if it does please mark brainliest