According to the valence number of copper(2+) and the same value for chlorine (1-) copper (II) chloride has the formula of CuCl2
The molar mass of copper is 0,0635 kg/mole and chlorine gas a molar mass of 0,035 kg/mole the compound will have a molar mass of ( 0,0635+2×0,035 )kg/mole=0,099kg/mole and 0,344 moles are equivalent in mass to 0,344×0,135 kg=0,046 kg
For this, you multiply the 12 two point shots she made to see how many points she earned
12 x 2 = 24
now you will subtract the 24 from 27 to find out how many points are left
27 - 24 = 3
this means she made 12 two point shots (worth 24 points) and 1 three point shot (worth 3 points) to total up as her 27 points:)
Answer:
N greater than or equal to -12
Step-by-step explanation:
N-8 greater than or equal to -4
N greater than or equal to -4-8
N greater than or equal to -12
Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Answer: No, I do not believe that there is enough convincing evidence to proof that he can control the dice.
When you roll a die, there is a 1/6 probability that you will roll a 6. If you multiply 50 by (1/6) you would expect your friend to roll at least 8 sixes.
He only rolled 3 more sixes than was expected. I would have him roll 50 more times at least to see how he does.
