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Arlecino [84]
3 years ago
6

Really easy math problem 5pts

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0
Given that it is an isosceles triangle ...

180 - 54 - 54 = 72°
tangare [24]3 years ago
5 0

Answer:

180 - 54 - 54 = 72°

Step-by-step explanation:

Hope I can help you :)

You might be interested in
Solve by the linear combination method.<br><br> 8g – 5h = 7<br> 4g + 10h = 1
Andreas93 [3]
In order to combine, you have to multiply the top equation by 2 so you get 8g + 10h = 8 8g - 10h = 4 --------------- 16g = 12 g = 3/4 --> plug it in to solve for h 8(3/4)-10h = 4 6-10h=4 10h=2 h=1/5 Your result: g=3/4, h=1/5
4 0
3 years ago
Please help me with this question !!!!
AlekseyPX
The distance of DC=HG,4.47; distance of CB=GF, 2.23; distance of BA=FE, 2.23; distance of AD=EH, 3.16


Answer:All sides are congruent so the shapes are congruent

Hope this helps :)
4 0
4 years ago
Help me out ? ty I’ll give brainliest
DaniilM [7]

Answer:

it will

Step-by-step explanation:

33.46

<em>hope</em><em> it</em><em> helps</em><em> and</em><em> your</em><em> day</em><em> will</em><em> full</em><em> of</em><em> happiness</em>

3 0
3 years ago
Just 7 and 8 please!!
77julia77 [94]
Just multiply it so multiply 59.89 x 4 and then for number 8 multiply 88.70 x 4
4 0
4 years ago
What is the solution to the equation 3/m+3-m/3-m=m^2+9/m^2-9
Bas_tet [7]

Answer:

  no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

  \dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

7 0
3 years ago
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