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Rzqust [24]
3 years ago
6

The data show the chest size and weight of several bears. Find the regression​ equation, letting chest size be the independent​

(x) variable. Then find the best predicted weight of a bear with a chest size of 50 inches. Is the result close to the actual weight of 407 ​pounds? Use a significance level of 0.05.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

Kindly go through the explanation for the answer.

Step-by-step explanation:

From the above calculated value we get the value are as:

n 6

sum(XY) 137925.00

sum(X) 278.00

sum(Y) 2954.00

sum(X^2) 12974.00

sum(Y^2) 1467334.00

b 11.3179

a -32.0607

Formula for regression equation are as:

y = -32.1 + 11.3x

when actual weight = 50

y = -32.1 + 11.3 X 50

= 532.9

The difference between the result and the 407 is 532.9 - 407 = 125.9, hence the result is very much different .

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Answer: it cost a customer $7.25 to buy five tulips and $10.5 to buy six roses.

Step-by-step explanation:

Let x represent the cost of 1 tulip.

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Multiplying equation 1 by 4 and equation 2 by 7, it becomes

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Answer:

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