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3 years ago

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The square root of 150 is between A.10 and 11B.11 and 12C.12 and 13 D.13 and 14

1 answer:

MrRissso [65]3 years ago

7 0

The square of 12 is 144 and the square of 13 is 169. Since 150 is in between those, it is C.

Hope this helps!

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there are 1024 players in a tennis tournament in each round half of the players are eliminated which function can be used to fin

jonny [76]

Answer: f(x) = 1,024(0.50)^x

Step-by-step explanation:

Hi, to answer this question we have to apply a decreasing rate formula:

f(x)= P (1 - r) ^x

Where:

p = original number of players

r = decreasing rate (decimal form, since half of the players are eliminated the percent decrease is 50%)

x = rounds

f(x) = number of players after x rounds

Replacing with the values given:

f(x) = 1,024(1-50/100)^x

f(x) = 1,024(1-0.5)^x

f(x) = 1,024(0.5)^x

7 0

3 years ago

What is the average rate of change of the function f(x)=5(2)^x from x = 1 to x = 5?

Mila [183]

Average rate of change refers to the slope of a function/equation.
To solve this, plug in for both x values and calculate the average, or mean.

x = 1
f(1) = 5(2)^1
= 5(2)
= 10

x = 5
f(5) = 5(2)^5
= 5(32)
= 160

Now, you calculate the average:
10 + 160 = 170
Divide by 2 and you get 85.

5 0

2 years ago

Complete the statement. Round to the nearest hundredth if necessary

Bond [772]

Answer:

$45.9$

Step-by-step explanation:

Remember that the hundredths place value is the second number after the decimal point and to round that number has to be greater than five in order to round up.

$1m=3.28084$

$3.28084\times14=45.93176$

Hundredths place value = 3

Round:

$3$

$=45.9$

Hope this helps.

8 0

2 years ago

Given the function f(x)=2x-1<br> Evaluate: <br>a) 2f(x) <br> b) f(2x)

Dmitrij [34]

Answer:

a) 2f(x) = 4x - 2

b) f(2x) = 4x - 1

Explanation:

Given function:

f(x) = 2x - 1

a) 2f(x)

2f(x) = 2(2x - 1)

= 4x - 2

b) f(2x)

f(2x) = 2(2x) - 1

= 4x - 1

3 0

1 year ago

2. Consider the function, f(x)=x^3+x^2-9x-9

Sedaia [141]

The intercepts of the graph are:

x-axis interception: $\left(-1,\:0\right),\:\left(-3,\:0\right),\:\left(3,\:0\right)$ .

y-axis interception: $\left(0,\:-9\right)$ .

See the graph of the function $f(x)=x^3+x^2-9x-9$ in the attached image.

<h3>Constructing a graph</h3>

For constructing a graph we have the following steps:

Determine the range of values for x of your graph.

For this exercise, for example, we can define a range -4<x<4. In others words, the values of x will be in this interval.

Determine the points

Replace these x-values in the given equation. For example:

When x=-4, we will have: $\left(-4\right)^3+\left(-4\right)^2-9\left(-4\right)-9=-21$ . Do this for the all x-values of your ranges.

See the results for this step in the attached table.

Draw the graph

Mark the points <u>x</u> and<u> y</u> that you found in the last step. After that, connect the dots to draw the graph.

The attached image shows the graph for the given function.

<h3>Find the x- and y-intercepts</h3>

The intercepts are points that crosses the axes of your plot. From your graph is possible to see:

x-axis interception points (y=f(x)=0) are: $\left(-1,\:0\right),\:\left(-3,\:0\right),\:\left(3,\:0\right)$ .

y-axis interception point (x=0) is: $\left(0,\:-9\right)$ .

Learn more about intercepts of the graph here:

brainly.com/question/4504979

5 0

2 years ago