Why wouldn’t you use a division to find an equivalent fraction for 7/15

1 answer:

wel3 years ago

4 0

To simplify a fraction by division you must have common factors between the denominator and the neominator to divide (or cancel) them

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Let f(x)=2x-1 and g(x)=x^2 -3. Find (f o g)(-3)

anzhelika [568]

(f o g)(-3) = (f(g(-3))
Because g is on the inside, we carry out g first.

g(x) = x^2 - 3
Substitute -3 in for x.
g(-3) = (-3)^2 - 3 = 9 - 3 = 6
g(-3) = 6

Next, carry out f on the result of g(-3)
f(6) = 2(6) - 1
= 12 - 1
= 11
So the answer is 11.

6 0

3 years ago

2x + 4 - 3x + 2 + 3x

KatRina [158]

Answer:

factor the expression:2(x+3

simply the expression:2x+6

Step-by-step explanation:

tell me if you don't get it

7 0

3 years ago

Judges in a diving competition gave scores of 9.3, 9 1/2, 9 4/5, 9.95 And 9 1/4. Which two scores were closest to one another?

Kazeer [188]

9.3 and $9\frac{1}{4}$ were closest to another.

Explanation

First we will convert each given fractions into decimal form. So....

$9\frac{1}{2}= 9+\frac{1}{2} = 9+0.50 =9.50\\ \\ 9\frac{4}{5}= 9+ \frac{4}{5}= 9+0.80=9.80\\ \\ 9\frac{1}{4}= 9+\frac{1}{4} =9+0.25= 9.25$

Then the scores are: 9.30, 9.50, 9.80, 9.95 and 9.25

So, 9.30 and 9.25 are closest to another as their difference is (9.30-9.25)=0.05

That means , 9.3 and $9\frac{1}{4}$ were closest to another.

6 0

3 years ago

Read 2 more answers

Mr. and Mrs.jones wanted to plan a fun day with there 2 children. An adult ticket to the local amusement park is $20. A child's

Burka [1]

The total amount for the family of for to the park is 28$

4 0

2 years ago

How to integrate with steps: (4x2-6)/(x+5)(x-2)(3x-1)

joja [24]

$\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx$

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

$\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}$

$\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)$

You can use the "cover-up" method here to easily solve for $a,b,c$ . It involves fixing a value of $x$ to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.