Answer:
DNA evidence revealed the American vultures share more recent ancestor with the Storks
Explanation:
The hooded vultures that is mostly found in the African continent have a close resemblance with the American vultures and were traditionally classified to belong to the Falcon family.
However, it was observed that the American vultures shared a similar behavior with Stork which is not common to the vulture found in Africa, including the hooded vulture. The Stork and the American vulture exhibit the behavior of urinating on their legs when being overheated. When the urine gets evaporated, it helps them to cool their body temperature.
This shared behavior between the storks and the American vultures led scientists into using molecular analysis in analyzing the DNA of the hooded vultures found in Africa, the American vultures, and the stork.
Evidence from the DNA analysis later revealed that the American vultures and the storks share a more common DNA sequences than African vultures and American vultures do.
Purple flowers is the correct answer because If there was a cross between both it would most likely be purple
Well, I may not name ALL of the minerals, but I can give you the names of some minerals I've known about:
1. Quartz
2. Magnetite
3. Mica
4. Diamond
But just to let you know, there are many minerals out here on Earth. All you have to do is either remember some minerals you know of, or just do some research.
It provides the reader with your topic and give them a central idea of your writing.
Answer:
0.8
Explanation:
There is a population where the frequencies of allele 1 and allele 2 are 0.7 and 0.3, respectively
Let's use GG to represent allele 1
Let's use gg to represent allele 2
So we can equally say that;
GG = p = 0.7
gg = q = 0.3 ( from Hardy-Weinberg Equilibrium)
So, given that the selection coefficient = 0.2
We known that the cross between GG and gg will definitely results to (GG,Gg and gg)
Then the fitness of these genes can be represented as:
1 - s, 1 and 1 - t respectively.
Thus. the allele 1's genotype fitness can be determined as
= 1 - s ( where s is the selection coefficient)
= 1 - 0.2
= 0.8
