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REY [17]
2 years ago
5

Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has

Mathematics
1 answer:
Feliz [49]2 years ago
6 0

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = \frac{1}{4}x

Sweets given to Raji = 5

Remaining sweets = 7

x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16

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3 years ago
Hollis put a layer of boxes in the bottom of a container. Each box has a volume of 1 cubic foot. The base layer of boxes in the
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2 years ago
If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)
sertanlavr [38]

Answer:

Final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

Step-by-step explanation:

given functions are f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

Now we need to find about what is the value of g\left(x\right)*f\left(x\right).

g\left(x\right)*f\left(x\right) simply means we need to multiply the value of  f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

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Hence final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

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2 years ago
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Answer:

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Step-by-step explanation:

<h3>Given</h3>
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