All categories

2 years ago

Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has

Mathematics

1 answer:

Feliz [49]2 years ago

6 0

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = $\frac{1}{4}x$

Sweets given to Raji = 5

Remaining sweets = 7

$x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16$

You might be interested in

The height, h, of a plant (in inches) w weeks since it was planted is represented by the equations h=3w+3. How many weeks will i

Hatshy [7]

Answer: 3 weeks

Step-by-step explanation:

We have to note firstly that 12 inches = 1 foot.

The equation given to represent the height in the question, h = 3w + 3.

The number of weeks that it will take the plant to reach one foot will then be:

h = 3w + 3

12 = 3w + 3

3w = 12 - 3

3w = 9

w = 9/3

w = 3

It'll take 3 weeks

7 0

3 years ago

Which of the following expressions are factors of p(x)=60x4+24x3−45x2−18x?

Whitepunk [10]

The factors are 3x, 4x^2-3 and 5x+2

So, Option B, C and F are correct.

Step-by-step explanation:

We need to find factors of the expression $p(x)=60x^4+24x^3-45x^2-18x$

Solving the expression: $p(x)=60x^4+24x^3-45x^2-18x$

Taking 3x common:

$p(x)=3x(20x^3+8x^2-15x-6)$

Now, factor by grouping, the terms inside the bracket.

$p(x)=3x((20x^3+8x^2)+(-15x-6))$

$p(x)=3x(4x^2(5x+2)-3(5x+2))$

$p(x)=3x(4x^2-3)(5x+2)$

So, the factors are 3x, 4x^2-3 and 5x+2

So, Option B, C and F are correct.

Keywords: Finding Factors

Learn more about finding factors at:

#learnwithBrainly

5 0

3 years ago

. . What needs to be corrected in the following construction for copying ∠ABC with point D as the vertex?.

SIZIF [17.4K]

From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.