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3 years ago

List the part ail products of 42×28

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

4 0

U can use the area model by doing 20*40=800 ,8*40=320 ,20*2=40 ,8*2=16

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Jenna takes a survey of students in her class to determine how many hours they studied for their Math exam. The mean of the resp

Reptile [31]

A) No one in the class studied more then 5 hours

5 0

3 years ago

Question 9<br><br> .....................................................................

egoroff_w [7]

Answer:

your answer is D (6.72)

Step-by-step explanation:

substitute x by 4

y = 2.76(4) - 4.4

y = 11.12 - 4.4

y = 6.72

Therefore the option D (6.72) is the correct answer

- hope this helps, if it does click the thanks button to let me know :) -

- have a nice day, be safe & healthy -

6 0

3 years ago

What is 4/ 3/5 plz help now I need it

arsen [322]

Answer: 20/3

Step-by-step explanation:

4/1 ÷ 3/5

4/1 ÷5/3

= 2-/3

8 0

3 years ago

Read 2 more answers

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

3 years ago

Please help! no links please!

svet-max [94.6K]

The value of x is: 75°

360° - 128° - 85° - 72° = 75°

4 0

3 years ago

Read 2 more answers