Using the mass of a proton 1.0073 amu and assuming it's diameter is1.0x10^-15, calculate the density of a proton in g/cm^3. I'm
not sure about how to convert amu to grams. Thanksfor the help!!
1 answer:
You just have to find a conversion from amu to grams. For every 1 amu, there is 1.66×10⁻²⁴ grams. Thus,
Mass of proton = 1.0073 amu * 1.66×10⁻²⁴ grams/amu = 1.672×10⁻²⁴ grams
Since a proton is spherical in shape, the volume would be:
Volume = 1/6*πd³ = 1/6*π(1.0×10⁻¹⁵ cm)³ = 5.236×10⁻⁴⁶ cm³
Therefore, the density is equal to
Density = Mass/Volume = 1.672×10⁻²⁴ grams/5.236×10⁻⁴⁶ cm³
Density = 3.2×10²¹ g/cm³
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Ca + 2HCl = CaCl₂ + H₂
c=4.50 mol/l
v=2.20 l
n(HCl)=cv
m(Ca)/M(Ca)=n(HCl)/2
m(Ca)=M(Ca)cv/2
m(Ca)=40g/mol·4.50mol/l·2.20l/2=198 g
198 grams of Ca are needed
Answer:
D is the answer may be. I'm not sure.
It’s C
Cooling a liquid til it freezes will cause a liquid to turn into a solid
