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Elan Coil [88]
3 years ago
12

In H2SO4, the oxidation number of H is , that of S is , and that of O is .

Chemistry
1 answer:
adell [148]3 years ago
4 0

Answer:

Explanation:

A) In H2SO4, the oxidation number of H is , that of S is , and that of O is .

In H₂SO₄ the oxidation sate of H is +1 (H₂= +2) that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why two hydrogen atoms are attached with one SO₄ to balance the charge.

B) In CaSO4, the oxidation number of Ca is , that of S is . , and that of O is .

In CaSO₄ the oxidation sate of Ca is +2 that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why one calcium atoms is attached with one SO₄ to balance the charge.

C) In HF, the oxidation number of H is , and that of F is .

In HF the oxidation state of hydrogen is +1 and that of fluorine is -1. Both form ionic compound.

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Answer:

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Explanation:

Applying the formulae of velocity,

V = d/t............. Equation 1

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From the question,

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Answer:

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Answer:

2 Transfer; very different

Explanation:

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The atoms that are involve in forming ionic compound have very different electronegativity . Electronegativity  is the measure of the ability of an atom to attract a bond pair of electron. For example the NaCl compound, the two atom has verse differences in the electronegativity. Cl atom is far more electronegative than Sodium atom.

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