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Elan Coil [88]
3 years ago
12

In H2SO4, the oxidation number of H is , that of S is , and that of O is .

Chemistry
1 answer:
adell [148]3 years ago
4 0

Answer:

Explanation:

A) In H2SO4, the oxidation number of H is , that of S is , and that of O is .

In H₂SO₄ the oxidation sate of H is +1 (H₂= +2) that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why two hydrogen atoms are attached with one SO₄ to balance the charge.

B) In CaSO4, the oxidation number of Ca is , that of S is . , and that of O is .

In CaSO₄ the oxidation sate of Ca is +2 that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why one calcium atoms is attached with one SO₄ to balance the charge.

C) In HF, the oxidation number of H is , and that of F is .

In HF the oxidation state of hydrogen is +1 and that of fluorine is -1. Both form ionic compound.

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NaOH has a molarity of 2.5 M and a volume of 4 Liters, how many moles are in<br> the solution?
Inga [223]

Answer:

10. mol NaOH

Explanation:

2.5 M = 2.5 mol/L

2.5 mol/L * 4 L = 10. mol

7 0
3 years ago
4) express 55mg in kilograms
artcher [175]
55 mg =

.00005500000 kg
6 0
3 years ago
How many grams of copper (II) hydroxide can be prepared from 2.4 grams of copper (II) nitrate (Cu(NO3)2 ) and excess sodium hydr
andreyandreev [35.5K]

Answer:

percentage yield = 67%

Explanation:

Mass of Cu(NO₃)₂  = 15.25 g

Mass of NaOH   = 12.75 g

Percentage yield = ?

Solution:

Cu(NO₃)₂ + 2NaOH   →  Cu(OH)₂ + 2NaNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 15.25 g /187.56 g/mol

Number of moles = 0.08 mol

Moles of NaOH :

Number of moles = mass/ molar mass

Number of moles = 12.75 g / 40 g/mol

Number of moles = 0.32 mol

Now we will compare the moles of Cu(OH)₂ with NaOH and Cu(NO₃)₂.      NaOH             :      Cu(OH)₂

                               2                   :          1

                               0.32              :           1/2×0.32 = 0.16 mol

                            Cu(NO₃)₂         :           Cu(OH)₂

                                  1                  :               1

                             0.08                :              0.08

The number of moles produced by  Cu(NO₃)₂  are less so it will limiting reactant.

Mass of Cu(OH)₂:

Mass = number of moles × molar mass

Mass = 0.08 mol × 97.6 g/mol

Mass = 7.808 g

Theoretical yield = 7.808 g

Percent yield:

percentage yield = Actual yield/ theoretical yield ×  100

percentage yield = 5.23 g/  7.808 g ×  100

percentage yield = 0.67 ×  100

percentage yield = 67%

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Why does every chemical reaction require a certain amount of activation energy?
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The answer could possibly be D.) The product have more potential than the activated complex OR C.) Forming the activated complex requires energy .

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