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3 years ago

In H2SO4, the oxidation number of H is , that of S is , and that of O is .

Chemistry

1 answer:

adell [148]3 years ago

4 0

Answer:

Explanation:

A) In H2SO4, the oxidation number of H is , that of S is , and that of O is .

In H₂SO₄ the oxidation sate of H is +1 (H₂= +2) that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why two hydrogen atoms are attached with one SO₄ to balance the charge.

B) In CaSO4, the oxidation number of Ca is , that of S is . , and that of O is .

In CaSO₄ the oxidation sate of Ca is +2 that of sulfur is +6 and O is -2 (O₄= -8)

In SO₄ the oxidation state is -2, because negative and positive charges are not equal. That's why one calcium atoms is attached with one SO₄ to balance the charge.

C) In HF, the oxidation number of H is , and that of F is .

In HF the oxidation state of hydrogen is +1 and that of fluorine is -1. Both form ionic compound.

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4 years ago

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lana66690 [7]

Answer:

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2 years ago

Which statements correctly describe the decay rates of radioactive isotopes?

storchak [24]

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Explanation:

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3 years ago

Read 2 more answers

A hydrogen atom requires a minimum energy of 2.18×10^-18 J atom to remove an electron from its ground state level. Determine whe

frosja888 [35]

Just find the energy of the <span>blueviolet light with a wavelength of 434.0 nm using the formula:

E = hc / lambda

E = energy
c= speed of light = 3 x 10^8 m/s
h = planck's constant = 6.6 x 10^{-34} m^2 kg / s
lambda = 434 nm = 434 x 10^{-9} m

Putting these values (with appropriate units) in the above formula :

we get: Energy, E = 4.5 x 10^{-19} J

E = 0.45 x 10^{-18} J

Now, the </span>minimum energy is 2.18×10^-{18} J but our energy is 0.45 x 10^{-18} J which is less.
<span>Means the electron will not be removed

</span>

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