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sukhopar [10]
2 years ago
14

Find out no. of moles present is 72 gm of water?

Chemistry
1 answer:
Alona [7]2 years ago
8 0
72g H2O x 1 mol H2O/18.02g H2O = 3.99 mol H2O 
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They are all things you can do to elements on the periodic table?
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PLEASE HELP!! What is the concentration [H3O+] of a solution with a pH of 13.2? Is the solution acidic, basic, or neutral?
Ilya [14]

The  concentration of [H3O+] will be 6.3 x 10^{-14} M

<h3>pH</h3>

Mathematically, pH = -log [H+] or -log [H3O+]

With a pH of 13.2:

      -log [H3O+] = 13.2

                     log [H3O+] = -13.2

                         [H3O+] = 6.3 x 10^{-14} M

More on pH can be found here: brainly.com/question/491373

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3 0
1 year ago
Read 2 more answers
In the food chain what might happen if all the frogs suddenly died off?
il63 [147K]
The food chain will crash.
7 0
3 years ago
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Which of Graphs 1 correctly represents the relationship between the pressure and volume of a gas?
Alborosie

Answer:

D

Explanation:

pressure is inversely proportional to gas volume

4 0
2 years ago
Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of c
Anna [14]

The question is incomplete. The complete question is

Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of calcium nitrate. A double displacement reaction occurs. What mass of each of the following substances is present when the reaction stops. A) potassium phosphate remaining B) calcium nitrate g remaining C) calcium phosphate formed D) potassium nitrate g formed

Answer:

a)84.91g

b)8.20g

c)316.4g

d)616.73g

Explanation:

The equation of the reaction:

2K3PO4(aq) + 3Ca(NO3)2 (aq)-------> 6KNO3(aq) + Ca3(PO4)2(s)

Molar mass of potassium phosphate= 212.27 g/mol

Amount of potassium phosphate= 500/212.27= 2.4 moles

Molar mass of calcium nitrate= 164.088 g/mol

Amount of calcium nitrate= 500/164.088=3.05moles

a) amount of potassium phosphate reacted according to reaction equation= 2 moles

Amount of potassium phosphate remaining= 2.4-2=0.4 moles

Mass of potassium phosphate remaining= 0.4×212.27=84.91g

b) Amount of calcium nitrate reacted according to reaction equation=3

Amount of calcium nitrate remaining=3.05-3= 0.05

Mass of calcium nitrate remaining= 0.05×164.088= 8.20g

c) since calcium nitrate is the limiting reactant, we use to estimate the mass of products formed.

From the reaction equation,

3 moles of calcium nitrate yields 1 mole of calcium phosphate

3.05 moles of calcium nitrate yields 3.05/3 = 1.02 moles of calcium phosphate

Molar Mass of calcium phosphate= 310.18 g/mol

Mass of calcium phosphate produced= 1.02×310.18= 316.4g

d)

3 moles of calcium nitrate yields 6 moles of potassium nitrate

3.05 moles of calcium nitrate yields 3.05×6/3= 6.1 moles of potassium nitrate

Molar mass of potassium nitrate = 101.1032 g/mol

Mass of potassium nitrate formed= 6.1× 101.1032= 616.73g

6 0
3 years ago
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