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pshichka [43]
3 years ago
10

Please help , I don't know about big bang I'm sorry

Chemistry
1 answer:
Tresset [83]3 years ago
3 0

1. When our Galaxy was forming why was the center dense?

Answer: <u>Stars are believed to originate as from gas clouds in space. Gravitational forces cause this gas to contract forming a dense center of gravitational force.Eventually this extreme pressure at the center of the star causes nuclear fusion reactions to occur.</u>

2. Why did hydrogen atoms collide in the dense center of the Galaxy?

Answer: <u>Compression would heat the gas to temperatures above 1,000 kelvins. Some hydrogen atoms would pair up in the dense, hot gas, creating trace amounts of molecular hydrogen. The hydrogen molecules would then start to cool the densest parts of the gas by emitting infrared radiation after they collide with hydrogen atoms.</u>

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True or false? Molecules are made of atoms of one type
Olegator [25]

Answer:

false

Explanation:

4 0
3 years ago
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In a 0.01 M solution of HCl, Litmus will be
Nadya [2.5K]
In a 0.01 M solution of HCl, Litmus will be red. Litmus paper will turn into red in acidic conditions. Hydrochloric acid is an acid. Litmus is an indicator for acidity and alkalinity made from inchens.
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HURRY IT'S URGENT!!!
Nady [450]

Answer:

convection

Explanation:

as air is heated, it rises up and away from the heat source, cools then falls closer to the heat source over and over again.

6 0
2 years ago
Which of these solutions is the most basic?
dalvyx [7]
<h2>Question↷</h2>

Which of these solutions is the most basic?

[OH-] = 4.3 x 10-9 M

[OH-] = 2.8 x 10-11 M

[OH-] = 6.7 x 10-10 M

[OH-] = 1.0 x 10-5 M

<h2>Answer↷</h2>

  • <u>[OH-] = 1.0 x 10-5 M</u> ✓

<h2>Solution↷</h2>

[OH-] = 4.3 x 10-9 M

  • [OH-] = 4.3 x 10^-9 M
  • pOH = - log [OH^1-]
  • pOH = - log [4.3 x 10^-9]
  • pOH = 8.36
  • pH = 14- 8.36
  • pH = 5.64

_______________________________________

[OH-] = 2.8 x 10-11 M

  • [OH-] = 2.8 x 10^-11 M
  • pOH = - log [OH^1-]
  • pOH = - log [2.8 x 10^-11 ]
  • pOH = 10.55
  • pH = 14-10.55
  • pH = 3.45

_______________________________________

[OH-] = 6.7 x 10-10 M

  • [OH-] = 6.7 x 10^-10 M
  • pOH = - log [OH^1-]
  • pOH = - log [6.7 x 10^-10]
  • pOH = 9.17
  • pH = 14-9.17
  • pH = 4.83

_______________________________________

[OH-] = 1.0 x 10-5 M

  • [OH-] = 1.0 x 10-5 M
  • pOH = - log [OH^1-]
  • pOH = - log [1.0 x 10^-5 ]
  • pOH = 5
  • pH = 14-5
  • pH = 9

_______________________________________

we know that , the solution with <u>pH > 7</u> is termed as basic and more the pH ,more the basicity, hence ,the solution with the highest pH would be the strongest base out of these all which is

<u>[OH-] = 1.0 x 10-5 M</u> with pH = 9

_______________________________________

4 0
2 years ago
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An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for
Lera25 [3.4K]

Answer:

100.5 ≈ 101

Explanation:

Km for S1 = 2.0 mM

Km for S2 = 20 mM

Given that : S1 = S2 =  hence Vmax for either S1 or S2 can represent

The Vmax can be calculated using the data Given and equation below

Vo = Vmax [s] / ( Km + [s] )  ------ (1)

Vo = 0.5

[s] = 0.1 mM

km = 20 mM

making Vmax subject of  equation 1

Vmax = 0.5 ( 20.1 mM) / (0.1 mM )

         = 100.5 ≈ 101

3 0
3 years ago
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