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bezimeni [28]
3 years ago
7

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, how many moles of Mg(OH)2 are produced for every mole of MgCl2?. A. 3. B. 1. C. 2.

D. 1/2
Chemistry
2 answers:
snow_tiger [21]3 years ago
5 0

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, 2 moles of KOH are produced for every mole of MgCI2. The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

aksik [14]3 years ago
4 0
Mole ratio:

<span> MgCl</span>₂<span> + 2 KOH = Mg(OH)</span>₂<span> + 2 KCl
</span>
1 mole MgCl₂ -------------- 1 mole Mg(OH)₂

Answer B

hope this helps!


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Relate the strength of a weak acid to the strength of a conjugate base.
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Answer:

There is a relationship between the strength of an acid (or base) and the strength of its conjugate base (or conjugate acid): The stronger the acid, the weaker its conjugate base.  The weaker the acid, the stronger its conjugate base.  The stronger the base, the weaker its conjugate acid.

explanation

The strength of an acid and a base is determined by how completely they dissociate in water. Strong acids (like stomach acid) break down or dissociate in water. Weak acids maintains their protons in water.

4 0
3 years ago
Discuss the reason for the presence of large number of organic compounds
jeyben [28]

Answer:

Carbon forms the large numbers of compound due to the following reasons

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(a) 4.12 x 10^15 atoms U
DochEvi [55]

Answer:

1.63ₓ10⁻⁶ g of U

139.03 g of H

0.385 g of O

141.8 g of Pb

Explanation:

In first place, we need to convert the number of atoms to moles, as we know that 1 mol of anything occupies 6.02×10²³ particles

Therefore:

4.12×10¹⁵ atoms of U . 1 mol / 6.02×10²³ atoms = 6.84×10⁻⁹ moles of U

8.37×10²⁵ atoms of H . 1 mol /6.02×10²³ atoms = 139.03 moles of H

1.45×10²² atoms of O . 1 mol /6.02×10²³ atoms = 0.0241 moles of O

4.12×10²³ atoms of Pb . 1 mol /6.02×10²³ atoms = 0.684 moles of Pb

Moles . Molar mass = Mass (g)

6.84×10⁻⁹ moles of U . 238.03 g/mol = 1.63ₓ10⁻⁶ g of U

139.03 moles of H . 1 g/mol = 139.03 g of H

0.0241 moles of O . 16 g/mol = 0.385 g of O

0.684 moles of Pb . 207.2 g/mol = 141.8 g of Pb

8 0
3 years ago
How many lead (Pb) atoms are in a 5.32 g sample of pure lead?
Elanso [62]

Answer:

1.55×10²² molecules.

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We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:

Mass of Pb = 5.32 g

Molar mass of Pb = 207 g/mol

Mole of Pb =?

Mole = mass /molar mass

Mole of Pb = 5.32/207

Mole of Pb = 0.0257 mole

Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:

From Avogadro's hypothesis,

I mole of Pb contains 6.02×10²³ molecules.

Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.

Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.

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What is a substrate?
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Answer:

D. a reactant that is catalyzed by an enzyme

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