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bezimeni [28]
3 years ago
7

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, how many moles of Mg(OH)2 are produced for every mole of MgCl2?. A. 3. B. 1. C. 2.

D. 1/2
Chemistry
2 answers:
snow_tiger [21]3 years ago
5 0

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, 2 moles of KOH are produced for every mole of MgCI2. The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

aksik [14]3 years ago
4 0
Mole ratio:

<span> MgCl</span>₂<span> + 2 KOH = Mg(OH)</span>₂<span> + 2 KCl
</span>
1 mole MgCl₂ -------------- 1 mole Mg(OH)₂

Answer B

hope this helps!


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Given the equation Ca + H2O --&gt; Ca(OH)2 + H2 how many grams of calcium will react completely with 10.0 grams of water? *
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Answer: 11.0 g of calcium will react with 10.0 grams of water.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

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\text{Number of moles}=\frac{10.0g}{18g/mol}=0.55moles

The balanced chemical equation is:

Ca+2H_2O\rightarrow Ca(OH)_2+H_2

According to stoichiometry :

2 moles of H_2O require = 1 mole of Ca

Thus 0.55 moles of H_2O require=\frac{1}{2}\times 0.55=0.275moles  of Ca  

Mass of Ca=moles\times {\text {Molar mass}}=0.275moles\times 40g/mol=11g

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Explanation:

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