Answer:
d) BaF2
Explanation:
The compound which is more soluble in an acidic solution than in a neutral solution is shown below:-
First we will compare acidic with Neutral
So,
Now, when we add H+ ions, so it will be
Then it will reduces F-, as BaF2 begin to form more aqueous ions, so, it will rises the solubility
Here we have explain that the maximum possible electrons present in nitrogen valence shell is 8 whereas in phosphorous 12 valence electrons are present.
Although both nitrogen (N) and phosphorous (P) belongs to the same series there are several properties which are different between both the element. The number of electrons present in nitrogen is seven which are present in the -s and -p orbitals. The electronic configuration of nitrogen is 1s²2s²2p³. In which the outermost electrons are the valence electrons i.e. 5 valence electrons are present. The maximum orbitals are possible under the principal quantum number 2 are -s and -p orbitals. Now the maximum capacity of the p orbital to contain 6 electrons, as it is half filled in nitrogen another 3 electrons can be incorporated. Thus the maximum number of electrons can be present in nitrogen is 10 among which 8 is the valence electrons.
On the other hand there are 15 electrons in phosphorous the electronic configuration is 1s²2s²2p⁶3s²3p³. Now the principal quantum number 3 can have three orbitals -s, -p and -d. So another 13 electrons can be incorporated (3 in -p orbital and 10 in -d orbital) among which upto 12 electrons can be its valence electrons.
Covalent compounds share with each other, whilst Ionic compounds take from each other.
Covalent compounds are composed of 2 or more NONMETALS.
So, it would be CO, since the rest of the compounds contain metals in them.
2 carbon, 4 nitrogen, 8 oxygen
Answer:
The answer is
<h2>2.00 %</h2>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
actual measurement = 46.37 g
error = 47.25 - 46.37 = 0.88
The percentage error of the measurement is
We have the final answer as
<h3>2.00 %</h3>
Hope this helps you