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8 months ago

Indicate the oxidation state for each of the following:

Chemistry

1 answer:

Nimfa-mama [501]8 months ago

6 0

P2H2 Oxidation State - Diphosphene

P2H2 has an oxidation number of +1. In P2H2, the oxidation

number of H is -1

H2C2O4 Oxidation State - Oxalic Acid

C has an oxidation number of +3 in H2C2O4. O has an oxidation

number of -2 in H2C2O4. H2C2O4 has an oxidation number of +1.

CrO2 Oxidation State - Chromium(IV) Oxide

CrO2 has an oxidation number of +4.

<h3>Explain oxidation?</h3>

The oxidation state, also known as the oxidation number, is an atom's hypothetical charge if all of its bonds to other atoms were fully ionic.

The sum of the oxidation states of all the atoms in an ion equals the ion's charge.

A substance's more electronegative element is given a negative oxidation state. The one that is less electronegative is given a positive oxidation state.

To learn more about oxidation refer to :

brainly.com/question/27239694

#SPJ13

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According to kinetic theory, which two factors are important for a successful

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Answer:A and B

Explanation: orientation and energy is all that matters

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2 years ago

Read 2 more answers

Boyle's Law represents the relationship of volume as pressure changes. The constants of Boyle's Law are:

Aleksandr [31]

Answer:

d. Temperature and number of molecules of gas

Step-by-step explanation:

Boyle's Law states, "The volume of a fixed mass of a gas is inversely proportional to the pressure if the temperature remains constant."

Let's examine the words.

"… volume…is inversely proportional to the pressure …" This means that volume and pressure are the <em>variables</em>.

"… fixed mass of a gas …" means that the number of molecules is constant.

"… temperature remains constant" speaks for itself.

a, c, and e are <em>wrong</em>, because pressure is a variable.

b is <em>wrong</em>, because volume is a variable.

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2 years ago

The formation of SO3 from SO2 and O2 is an intermediate step in the manufacture of sulfuric acid, and it is also responsible for

jeka57 [31]

Answer:

118.22 atm

Explanation:

2SO₂(g) + O₂(g) ⇌ 2SO₃(g)

KP = 0.13 = $\frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}$

Where p(SO₃) is the partial pressure of SO₃, p(SO₂) is the partial pressure of SO₂ and p(O₂) is the partial pressure of O₂.

With 2.00 mol SO₂ and 2.00 mol O₂ if there was a 100% yield of SO₃, then 2 moles of SO₃ would be produced and 1.00 mol of O₂ would remain.
With a 71.0% yield, there are only 2*0.71 = 1.42 mol SO₃, the moles of SO₂ that didn't react would be 2 - 1.42 = 0.58; and the moles of O₂ that didn't react would be 2 - 1.42/2 = 1.29.

The total number of moles is 1.42 + 0.58 + 1.29 = 3.29. With that value we can calculate the molar fraction (X) of each component:

XSO₂ = 0.58/3.29 = 0.176

XO₂ = 1.29/3.29 = 0.392

XSO₃ = 1.42/3.29 = 0.432

The partial pressure of each gas is equal to the total pressure (PT) multiplied by the molar fraction of each component.

p(SO₂) = 0.176 * PT

p(O₂) = 0.392 * PT

p(SO₃) = 0.432 * PT

Rewriting KP and solving for PT:

$\frac{p(SO_{3})^{2}}{p(SO_{2})^{2}p(O_{2})}=0.13\\\frac{(0.432*P_{T})^{2}}{(0.176*P_{T})^{2}(0.392*P_{T})} =0.13\\\frac{0.1866*P_{T}^{2}}{0.0121*P_{T}^{3}} =0.13\\\frac{15.369}{P_{T}}=0.13\\P_{T}=118.22 atm$

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3 years ago

Reaction rate is expressed in terms of changes in the concentration of reactants and products. Write a balanced equation for the

KengaRu [80]

Answer : The balanced equations will be:

$CH_4+2O_2\rightarrow 2H_2O+CO_2$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

$Rate=-\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2O]}{dt}=+\frac{d[CO_2]}{dt}$

The balanced equations will be:

$CH_4+2O_2\rightarrow 2H_2O+CO_2$

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2 years ago

Herbicides break down dead organisms into humus. True or False?

Rzqust [24]

Answer:

true

Explanation:

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2 years ago