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bonufazy [111]
3 years ago
15

Unlike images produced by a convex spherical mirror, images produced by concave spherical mirrors A. are always going to be disp

layed upright, not inverted. B. can be real or virtual depending on the object's placement. C. are located only by the mirror. D. are always going to be virtual.
Physics
2 answers:
posledela3 years ago
7 0

The correct choice is

B. can be real or virtual depending on the object's placement

When the object is placed beyond the radius of curvature of the mirror, the mirror produces real, inverted and smaller image of the object.

When the object is placed between the radius of curvature of the mirror and the focal point, the mirror produces real, inverted and larger image of the object.

When the object is placed at the radius of curvature of the mirror , the mirror produces real, inverted and equal size image of the object.

When the object is placed closer than the focal point, the mirror produces virtual, erect and larger image of the object.

Jobisdone [24]3 years ago
6 0
Option B. Images can be real or virtual depending on the object´s placement.

If the object is to the right of the focal point the image will be virutal and if the object is to the left of the focal point the image will be real.
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A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

T = tension

Put the value into the formula

v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}

v =519.61\ m/s

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
3 years ago
Xamine the graph. Select the statement that best describes the energy change in the particles of a substance during melting.
lesya692 [45]

Answer:

  • Option B) Absorbed energy results in the change in potential energy.

Explanation:

Please, find attached the graph that accompanies this question.

The<em> melting</em> proces is the change from solid phase to liquid phase. It is represented with the lower flat line with the symbol ΔHfus over it.

The line is flat because the temperature remains constant during this process. Thus, you know the option "C) As the temperature increases during melting, the kinetic energy also increases" is FALSE.

What happens during this process is:

  • Most of the energy received by the particles from heating, during the melting process, goes to overcome the intermolecular bonds between the particles. This results in increasing the distance between the particles, so the internal potential energy increases. This is what the option <em>"B) Absorbed energy results in the change in potential energy" correctly describes.</em> Hence, option B) is TRUE.

Althoug most of the heat energy received is transformed into potential energy, yet a small part of the heat energy increases a bit the kinetic energy of the particles, because the particles will vibrate faster around their relatively fixed positions. Hence, the option "<em>A) The kinetic energy of the particles remains unchanged</em>" is FALSE.

As for option D) it is not reasonable at all: none chemical or physical priciple can be used to state that <em>the kinetic energy decreases as the particles move farther apart</em>. Thus, this is FALSE.

6 0
3 years ago
Gamma rays are a type of very high frequency wave. This means that gamma rays must have a _____.
agasfer [191]

Gamma waves have a short wavelength. The closer the wavelength  (\lambda) the higher frequency the wave is

4 0
4 years ago
Read 2 more answers
Jo wants to find out about floating and sinking. She puts a rubber duck and a bar of soap in a
maks197457 [2]

Answer:

the soap sinks because it is more dense than the duck.

7 0
3 years ago
A 1000 kg satellite and a 2000 kg satellite follow exactly the same orbit around the earth. What is the ratio F1/F2 of the gravi
Tamiku [17]

Answer:

the <em>ratio F1/F2 = 1/2</em>

the <em>ratio a1/a2 = 1</em>

Explanation:

The force that both satellites experience is:

F1 = G M_e m1 / r²       and

F2 = G M_e m2 / r²

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • r is the orbital radius
  • M_e is the mass of Earth

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

<em>F1/F2 = 1/2</em>

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r    and

F2c = m2 v² / r

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • v is the orbital velocity
  • r is the orbital velocity

Thus,

a1 = v² / r ⇒ v² = r a1    and

a2 = v² / r ⇒ v² = r a2

Therefore,

F1c = m1 a1 r / r = m1 a1

F2c = m2 a2 r / r = m2 a2

In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,

F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

also

a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

<em>a1/a2 = 1</em>

4 0
3 years ago
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