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butalik [34]
3 years ago
5

If a machine exerts a force of 250 N on an object and no work is done, what must have occurred?

Physics
1 answer:
valina [46]3 years ago
8 0

Answer:

<h2>1) There is no work done by the machine because</h2><h2>B) The object has not moved</h2><h2>2) There is no work done by the prisoner because</h2><h2>D) The prisoner does no work because the wall goes no distance</h2><h2>3) The kinetic energy when it is half the way down is</h2><h2>6.0 J</h2>

Explanation:

1) As we know that the work done is the product of force and displacement

It is given as

W = Fdcos\theta

so if the object is not displaced due to the force exerted by the object then the work done by the object must be ZERO

so correct answer is

B) The object has not moved

2) As we know that the work done is the product of force and displacement

It is given as

W = Fdcos\theta

As we know that the wall is not displaced due to applied force so here work done by the prisoner must be zero

D) The prisoner does no work because the wall goes no distance

3) As we know by work energy theorem that work done by all forces is equal to change in its kinetic energy

So we will have

W_g + W_f = \frac{1}{2} mv^2

so we will have

3(10)(4) + W_f = \frac{1}{2}(3)(3)^2

120 + W_f = 13.5

W_f = -106.5 J

now when cart moves half the distance then again using the same

W_g + W_f = K

K = 3(10)(2) - \frac{106.5}{2}

K = 6.5 J

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Answer:

The magnetic induction of the magnetic field is  0.0005293 mT

Explanation:

Data given

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r = 23 cm = the radius of the wire = 0.23 meter

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I(enclosed) = (I* r'²)/ (r ²)  

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with r' = the distance of point from the center of wire  0.02 meter

We plug this into ampere's law:

∮ *B *dl =μ 0  * (I* r'²)/ (r ²)  

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with dl = an infinitesimal element (a differential) of the curve C

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We can simplify this, by using an Amperian loop can write this as:

B *( 2 π r') =  μ 0  * (I* r'²)/ (r ²)  

Because the circumference of a circle is  2 π r , when we integrate over length at a distance  r ′  from the center of wire whose crossection is a circle we get  2 π r ′

When we isolate B, we get:

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6 0
3 years ago
During soccer practice, Maya kicked a soccer ball 37° off the ground at 25 m/s. What was the ball's speed 2.2 s after she kicked
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<u>Answer</u>

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<u>Explanation</u>

The motion apply the equations of Newton's law of motion. The ball is acceleration is -9.8 m/s² (acceleration due to gravity. It is negative because the ball is going against gravity, so it is decelerating).

The first equation of Newton's law of motion is;

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V = 25 + (-9.8 × 2.2)

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