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salantis [7]
2 years ago
9

The force of replusion between two like charged particles will increase if​

Physics
1 answer:
Alex_Xolod [135]2 years ago
7 0

Answer:

The distance of separation is decreased

Explanation:

From Cuolomb's law, we know that the strength of charge is inversely proportional to the distance of separation between the charges. To mean that increasing the distance let's say from 2m to 3 m would mean initial strength getting form 1/4 to 1/9 which is a decrease. The vice versa is true hence the force of repulsion can increase only when we decrease the distance of separation.

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a shopper pushes a cart 40.0m south down one aisle and then turns 90.0 degrees and moves 15.0m. He then makes another 90.0 degre
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Answer:

Explanation:

The displacement is the distnce of the shopper from the starting point.

Sum of movement along the vertical = 40-20 = 20m

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A sled is at rest at the top of a slope 2 m high. The sled has a mass of 45 kg. What is the sled's potential energy?
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Answer:

PE = 882 J

Explanation:

Through the International System we know that the gravity of the earth is 9.8 m/s², so...

Data:

  • m = 45 kg
  • g = 9.8 m/s²
  • h = 2 m
  • PE = ?

Formula:

  • \boxed{\bold{PE=m*g*h}}

Replace and solve:

  • \boxed{\bold{PE=45\ kg*\ 9.8\frac{m}{s^{2}}*2\ m}}
  • \boxed{\boxed{\bold{PE=882\ J}}}

The potential energy of the sled is <u>882 Joules</u>.

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