Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!
Humans,trees,plants hope it helps
Answer:
a) Electric potential = 853 V
b) Electron speed at point B, if at Point A, the speed were zero = 1.732 × 10⁷ m/s
Explanation:
For an electron moving in an electric field with potential V,
Work done = qV where q is the charge on the electron
And the Work done is equal to the change in kinetic energy of the electron
qV = m(v₂² - v₁²)/2
V = m(v₂² - v₁²)/2q
q = 1.602 × 10⁻¹⁹C
m = 9.11 × 10⁻³¹ kg
v₁= 10⁷ m/s
v₂ = 2 × 10⁷ m/s
Putting these values in for the variables and solving
V = 853 V
b) If the electron started from rest,
qV = mv²/2
v = √(2qV/m) =√((2 × (1.602 × 10⁻¹⁹) × 853)/(9.11 × 10⁻³¹)) = 1.732 × 10⁷ m/s
Answer:
Wavelength is calculated as 213.9 nm
Solution:
As per the question:
Wavelength of light = 570 nm
Time, t = 16.5 ns
Thickness of glass slab, d = 0.865 ns
Time taken to travel from laser to the photocell, t' = 21.3
Speed of light in vacuum, c = ![3\times 10^{8}\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E%7B8%7D%5C%20m%2Fs)
Now,
To calculate the wavelength of light inside the glass:
After the insertion of the glass slab into the beam, the extra time taken by light to cover a thickness t = 0.865 m is:
t' - t = 21.3 - 16.5 = 4.8 ns
Thus
![\frac{d}{\frac{c}{n}} - \frac{d}{v} = 4.8\times 10^{- 9}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B%5Cfrac%7Bc%7D%7Bn%7D%7D%20-%20%5Cfrac%7Bd%7D%7Bv%7D%20%3D%204.8%5Ctimes%2010%5E%7B-%209%7D)
![\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}](https://tex.z-dn.net/?f=%5Cfrac%7B0.8656%7D%7B%5Cfrac%7Bc%7D%7Bn%7D%7D%20-%20%5Cfrac%7B0.865%7D%7Bv%7D%20%3D%204.8%5Ctimes%2010%5E%7B-%209%7D)
where
n = refractive index of the medium
v = speed of light in medium
![\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}](https://tex.z-dn.net/?f=%5Cfrac%7B0.8656%7D%7B%5Cfrac%7Bc%7D%7Bn%7D%7D%20-%20%5Cfrac%7B0.865%7D%7Bv%7D%20%3D%204.8%5Ctimes%2010%5E%7B-%209%7D)
![n = \frac{4.8\times 10^{- 9}\times 3.00\times 10^{8}}{0.865} + 1](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B4.8%5Ctimes%2010%5E%7B-%209%7D%5Ctimes%203.00%5Ctimes%2010%5E%7B8%7D%7D%7B0.865%7D%20%2B%201)
n = 2.66
Now,
The wavelength in the glass:
![\lambda' = \frac{\lambda }{n}](https://tex.z-dn.net/?f=%5Clambda%27%20%3D%20%5Cfrac%7B%5Clambda%20%7D%7Bn%7D)
![\lambda' = \frac{570}{2.66} = 213.9\ nm](https://tex.z-dn.net/?f=%5Clambda%27%20%3D%20%5Cfrac%7B570%7D%7B2.66%7D%20%3D%20213.9%5C%20nm)