The force of replusion between two like charged particles will increase if
1 answer:
You might be interested in
Answer:
1070 Hz
Explanation:
First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:
The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength .
Hence, we have
.
The speed of a wave is the product of its wavelength and its frequency.
Answer:
g'(10) =
Explanation:
Since g is the inverse of f ,
We can write
g(f(x)) = x <em> </em><em>(Identity)</em>
Differentiating both sides of the equation we get,
g'(f(x)).f'(x) = 1
g'(10) = --equation[1] Where f(x) = 10
Now, we have to find x when f(x) = 10
Thus 10 = + 2
= 8
x =
Since f(x) = + 2
f'(x) = -
f'() = -4 × 4 = -16
Putting it in equation 1, we get:
We get g'(10) = -
Answer:
The number is
Explanation:
From the question we are told that
The wavelength is
The length of the glass plates is
The distance between the plates (radius of wire ) =
Generally the condition for constructive interference in a film is mathematically represented as
Where t is the thickness of the separation between the glass i.e
t = 0 at the edge where the glasses are touching each other and
t = 2d at the edge where the glasses are separated by the wire
m is the order of the fringe it starts from 0, 1 , 2 ...
So
=>
=>
given that we start counting m from zero
it means that the number of bright fringes that would appear is
=>
=>