Answer:
See below
Explanation:
East components are 10 and 12 cos 30 = 20.392 m/s
North component = 12 sin 30 = 6 m/s
Resultant velocity = sqrt ( 20.392^2 + 6^2) = <u>21.26 m/s </u>
direction arc tan (6/20.392) = <u>16.4 degrees N of east </u>
It’s definitely b Yk Why um I don’t really know butttt gut instinct
Answer:
Explanation:
Let the initial velocity of small block be v .
by applying conservation of momentum we can find velocity of common mass
25 v = 75 V , V is velocity of common mass after collision.
V = v / 3
For reaching the height we shall apply conservation of mechanical energy
1/2 m v² = mgh
1/2 x 75 x V² = 75 x g x 10
V² = 2g x 10
v² / 9 = 2 x 9.8 x 10
v² = 9 x 2 x 9.8 x 10
v = 42 m /s
small block must have velocity of 42 m /s .
Impulse by small block on large block
= change in momentum of large block
= 75 x V
= 75 x 42 / 3
= 1050 Ns.
Answer:
λ = 482.05 nm
Explanation:
The diffraction phenomenon and the diffraction grating is described by the expression
d sin θ = m λ
where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction
in this case they indicate the distance between slits, the angle and the order of diffraction
λ = 
d sin θ / m
let's calculate
λ = 1.00 10⁻⁶ sin 74.6 / 2
λ = 4.82048 10⁻⁷ m
Let's reduce to nm
λ = 4.82048 10⁻⁷ m (10⁹ nm / 1 m)
λ = 482.05 nm
Answer:
Explanation:
100 mph = 100 x 1760 x 3 / ( 60 x 60 )
= 146.67 ft / s
70 mph = 70 x 1760 x 3 / ( 60 x 60 )
= 102.67 ft/s
Let mass of the ball = m .
The ball which was moving with a velocity of 146.67 ft/s is turned back by the action of force of bat on the ball and it moved in opposite direction with velocity of - 102.67 ft/s ( - ve sign due to reversed direction )
If m be the mass of ball
change in momentum = m x 146.67 - ( - m x 102.67 )
= m x 146.67 + m x 102.67
= 249.34 m
Change in momentum = impulse = force x time
Putting the given values
249.34 m = force x 1 x 10⁻³ ( time = 10⁻³ s )
force = 249.34 m x 10³ poundal .
Here m is mass of the ball in lb .
