Answer:
0.3097 moles of an nonionizing solute would need to be added.
Explanation:
Molal elevation constant = ![k_b=1.22^oC/m](https://tex.z-dn.net/?f=k_b%3D1.22%5EoC%2Fm)
Normal boiling point of ethanol = ![T_o=78.4^oC](https://tex.z-dn.net/?f=T_o%3D78.4%5EoC)
Boiling of solution =![T_b=86.30^oC](https://tex.z-dn.net/?f=T_b%3D86.30%5EoC)
Moles of nonionizing solute = n
Mass of ethanol (solvent) = 47.84 g
Elevation boiling point:
![\Delta T_b=T_b-T_o](https://tex.z-dn.net/?f=%5CDelta%20T_b%3DT_b-T_o)
![\Delta T_b=86.30^oC-78.4^oC=7.9^oC](https://tex.z-dn.net/?f=%5CDelta%20T_b%3D86.30%5EoC-78.4%5EoC%3D7.9%5EoC)
![\Delta T_b=K_b\times m](https://tex.z-dn.net/?f=%5CDelta%20T_b%3DK_b%5Ctimes%20%20m)
![m=\frac{\text{Moloes of solute}}{\text{Mass of solvent(kg)}}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B%5Ctext%7BMoloes%20of%20solute%7D%7D%7B%5Ctext%7BMass%20of%20solvent%28kg%29%7D%7D)
![7.9^oC=1.22^oC/m\times \frac{n}{0.04784 kg}](https://tex.z-dn.net/?f=7.9%5EoC%3D1.22%5EoC%2Fm%5Ctimes%20%5Cfrac%7Bn%7D%7B0.04784%20kg%7D)
n = 0.3097 mol
0.3097 moles of an nonionizing solute would need to be added.
<u>Answer:</u> The structure of the geometrical isomers are attached below.
<u>Explanation:</u>
Cis- and Trans- isomers are the geometrical isomers which have same chemical formula but different structural formula
According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.
If the highest priority groups are on the same side, it is known as cis-form and if the highest priority groups are on opposite side, it is known as trans-form.
We are given a chemical compound, which is 2-pentene.
In this the highest priority groups are methyl and ethyl groups.
When the groups are on the same side, it forms cis-form and when the groups are on the opposite side, it forms trans-form
The structure of the geometrical isomers are attached below.
Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
<h3>What are the products of
Uranium-238 and Thorium -228?</h3>
If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.
So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
Learn more about isotope here: brainly.com/question/14220416
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Answer:
The heat capacity for the sample is 0.913 J/°C
Explanation:
This is the formula for heat capacity that help us to solve this:
Q / (Final T° - Initial T°) = c . m
where m is mass and c, the specific heat of the substance
27.4 J / (80°C - 50°C) = c . 6.2 g
[27.4 J / (80°C - 50°C)] / 6.2 g = c
27.4 J / 30°C . 1/6.2g = c
0.147 J/g°C = c
Therefore, the heat capacity is 0.913 J/°C
Answer:
<h2>The answer is 40 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
<h3>force = mass × acceleration</h3>
From the question
mass = 50 kg
acceleration = 0.8 m/s²
We have
Force = 50 × 0.8
We have the final answer as
<h3>40 N</h3>
Hope this helps you