Answer:
1.30 mol P
Explanation:
take what is given to you (40.4g). now divide it by the molar mass of the asked element (phosphorus = 30.97g/mol)
40.4g P / 30.97g/mol P = 1.30 mol P
hope this helps :)
I think it would be ionization
Solution
Given mass of FeBr2 = 85.5 g
Molar mass of FeBr2 = 215.65
No. of Moles of FeBr2 = Given Mass / Molar mass = 85.5 / 215.65
No. of Moles = 0.3964
Given Volume is 450 mL i.e. 0.450 L
Now Concentration = 0.3964/0.450
Hence Concentration = 0.881 mol/L
Answer:
3.47 mol MnSO4
Explanation:
54.94 + 32.07 + (16 × 4) = 151.01g/mol MnSO4
542.32g / 151.01g/mol = 3.47 mol MnSO4
