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alekssr [168]
2 years ago
7

A bowling ball is let go from a height of 30 cm. What is the velocity of the

Chemistry
1 answer:
marishachu [46]2 years ago
6 0

Answer:

The answer is 0.30 m/s

Explanation:

i search it on

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Given the speed of light as 3.0 × 108 m/s, calculate the wavelength of the electromagnetic radiation whose frequency is 7.5 × 10
arlik [135]
Wavelength= velocity/frequency
wavelength= (3.0 x 10^8m/s) / 7.5 x 10^12 Hz)
you can do the math
I am assuming u that 108 is 10^8 and the 1012 is 10^12
3 0
3 years ago
What is the correct prefix for 3 <br> tri-<br> di-<br> mono-<br> tetra-
Ivenika [448]

Answer:

tri-

Explanation:

Examples could be Tri-angle, Tri-cycle, Tri-ceratops

5 0
2 years ago
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Which metalloid has three valence electrons? 1. Lithium 2. boron 3. silicon 4. aluminum 5. arsenic 
iren [92.7K]

Answer:

boron

Explanation:

5 0
3 years ago
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A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
Which or these equations is balanced H2SO4 + 2Al &gt; Al2(SO4)3 + H2 or 2KCl + Pb(NO3)2 &gt; 2KNO3 + PbCl2
Dmitry_Shevchenko [17]

Balancing of chemical equation is essential because of the law of conservation of mass, which states that the mass of a system can not be created or removed.

The second equation is balanced

2KCl_(_a_q_) +Pb(NO_3)_2_(_a_q_) ==> 2KNO_3_(-a_q_) + PbCl_2(_a_q_)

This is because the number of elements of each atom in the product side equal the number of elements of each atom on the reactant side.

The first equation is not balanced

H_2SO_4 _(_a_q) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + H_2_(_g_)

This is because there is 1 molecule of SO_4^{-2} on reactant side as compared to 3 molecules of SO_4^{-2}

To balance the equation we add a coefficient of 3 on sulphuric acid (H_2SO_4) and a coefficient of 3 on hydrogen (H_2)

3H_2SO_4_(_a_q_) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + 3H_2_(_g_)

7 0
3 years ago
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