Which prime number do the prime factorization of 130 and 165 have in common?

3241004551 [841]

Answer:

$\frac{5x - 8}{3}$

Step-by-step explanation:

Find the LCM of the denominators and then solve:

$\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\$

$\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\\frac{3(4x - 5) - 2x - 1}{6} \\\\\frac{12x - 15 - 2x - 1}{6}\\\\\frac{10x - 16}{6}\\\\ \frac{2(5x - 8)}{2 * 3} \\\\ \frac{5x - 8}{3}$

4 0

2 years ago

there are approximately 3 million births in the unitad states each year .find the birth rate per minute

juin [17]

Answer:

Approx. 6 b/m

Step-by-step explanation:

Find out How many minutes in a year which is 525600 then divide that by 3,000,000 which makes 5.7077 so rounded is 6.

3 0

1 year ago

Read 2 more answers

The two-way table shows the number of students that would rather be a member of the band or chorus if they could only choose one

sergey [27]

Answer:

There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.

There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.

Students in Grade 8 are more likely to be members of the band.There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.

There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.

Students in Grade 8 are more likely to be members of the band.

4 0

2 years ago

Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

5 0

2 years ago

You can choose from groups of 2, 3, or 5 balloons, and you can choose to have them tied together with either a red ribbon or a b

vesna_86 [32]

6 different outcomes

5 0

2 years ago