If by "long leg lengths" you mean the hypotenuse then the area is 116 sq. units. If you mean the bases of the triangles then the area is 170 sq. units.
If the length of 12 is the hypotenuse, we first must find the base of the triangles using the Pythagorean theorem:
10² + b² = 12²
100 + b² = 144
b² = 44
b = √44 = 6.6
This means we have two triangles and a rectangle. The area of the rectangle is 5(10) = 50 sq. units. The area of each triangle is 1/2(6.6)(10) = 33. Adding all 3 together we have:
50+33+33 = 116 sq. units.
If the 12 is the base, then we have the rectangle with the area of 5(10) = 50 and two triangles each with an area of 1/2(12)(10) = 60:
50+60+60 = 170 sq. units.
t(1) = 1 = 2(1)-9 / 1 - a
1 - a = 2 - 9 = -7
a = 1 + 7
a = 8 answer
P of a rectangle= 2l + 2w
P = 2(48) + 2(20)
P= 96 + 40
P= 136m
The length of the rectangle is 136 meters.
I hope that helped.
Answer:
Solution,
x+12+8x-2=180° (Linear pair)
or, 9x+10=180°
or, x+10=180/9
or, x=20-10
x=10
The length of MT
=8x-2
=8×10-2
=80-2
=78
hope it helps you
Answer:
(40 + 2x)feet
Step-by-step explanation:
see attachment for the figure.
Let 'L' represents the length of the rectangular swimming pool i.e 40ft wide.
and pool is bordered by square tiles that are x feet in length surrounding the pool
therefore,
In order to find the longest side of the pool and the tile border, take the sum of length of the swimming pool i.e 40 adding two times the wide of the square tiles
(40+2x)feet.
