Answer:
(2, 5 )
Step-by-step explanation:
Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= - 
y = 3x² - 12x + 17 ← is in standard form
with a = 3 and b = - 12, thus
= - 
= 2
Substitute x = 2 into the function for corresponding value of y
y = 3(2)² - 12(2) + 17 = 12 - 24 + 17 = 5
vertex = (2, 5 )
A I’m pretty sure is correct answer
Let's make a table of differences
0 3 8 15 24
3 5 7 9
2 2 2
Constant second difference means a quadratic polynomial,
f(n)=an² + bn +c
f(1)=0, f(2)=3, f(3)=8
0 = a+b+c
3 = 4a + 2b + c
8 = 9a + 3b + c
Subtracting pairs
3 = 3a+b
5 = 5a + b
Subtracting,
2 = 2a
a = 1
b = 5 - 5a = 0
c = -a-b = -1
f(n)=n² -1
Duh, shoulda noticed that at the beginning.
f(17)=17²-1 = 288
a₁ =5
aₙ = aₙ₋₁ - 7
aₙ = a₁ + d(n-1)
aₙ = 5 - 7(n-1)
a₇ = 5 - 7(6) = -37
Answer: -37
Answer:
9
Step-by-step explanation:
x^2
Let x=-3
(-3)^2
-3*-3
9
Answer:
(10, -20).
Step-by-step explanation:
y= -5x + 30
x = 10
Substitute x = 10 in the first equation:
y = -5*10 + 30
y = -50 + 30
y = -20.
So the solution is (10, -20).
