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4 years ago

The _____ along a gene specifies the type of protein that will be produced.

Chemistry

1 answer:

Liula [17]4 years ago

5 0

I believe the answer to this is d.

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You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el

Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.

For example;

Given a number 5;

We know the number is made of both the atomic number of the element and the highest quantum number.

It is easier for us to know the highest quantum number from the shell notation:

shell notation 1s²2s²2p¹

highest principal quantum number is 2

We are left with atomic number 5-2, which is 3

The element is therefore Li.

Part A. 5, 30, 58, 56, 99, 79, 19, 98, 9

Li Fe I Sb U Ta S Pa N

Part B. 9, 99, 30, 95, 19, 47, 79

N U Fe Ra S Mo Ta

Learn more:

s-orbital brainly.com/question/9288609

#learnwithBrainly

4 0

3 years ago

A container of argon with a volume of 22 ml has a pressure of 101.0 kPa.

Alexeev081 [22]

Answer:

The new pressure is 44.4 kPa.

Explanation:

We have,

Initial volume, $V_1=22\ ml$

Initial pressure, $P_1= 101.0\ kPa$

It is required to find the new pressure when the volume is increased to 50 ml. The relationship between pressure and volume is known as Boyle's law.

$PV=k\\\\P_1V_1=P_2V_2$

$P_2$ is final pressure

$P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa$

So, new pressure is 44.4 kPa.

6 0

3 years ago

What is the molarity of a stock solution if 60 mL were used to make 150 ml of a .5M solution?

olga2289 [7]

The molarity of the stock solution is 1.25 M.

Explanation:

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

V1 = 150 ml

M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $$\frac{V1M1}{V2}$

Plugin the values as,

M2 = $$\frac{150 \times 0.5}{60}$

= 1.25 M

So the molarity of the stock solution is 1.25 M.

4 0

3 years ago

Acids are used to make... 1. mortar and cement 2. baking soda 3. car batteries

mr Goodwill [35]

That is correct! Great Job High School!

7 0

4 years ago

What is the oxidation number for iodine in Mg(IO3)2 ?

mestny [16]

The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as
Mg(IO3)2
MgI2O6
As we know that
Mg has +2
O has -2
So,
(+2) + 2I + 6 (-2)=0
2 + 2I - 12 =0
10+ 2I =0
10 = 2I
I =5

6 0

3 years ago

Read 2 more answers