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Yuri [45]
4 years ago
6

in the cell, newely made proteins move directly from the ribosomes into the rough _____ _____, where they are chemically modifie

d
Chemistry
1 answer:
olga nikolaevna [1]4 years ago
8 0

Answer:

endoplasmic reticulum

Explanation:

there it is

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Particles that make up matter are in constant motion true or false
Sladkaya [172]
The statement is true
7 0
3 years ago
"benzyl ethyl ether reacts with concentrated aqueous hi to form two initial organic products (a and b). further reaction of prod
ahrayia [7]

Answer:

See below.  

Step-by-step explanation:

Ethers react with HI at high temperature to produce an alky halide and an alcohol.

R-OR' + HI ⟶ R-I + H-OR'

<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.

  1. PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻    Protonation of the ether
  2. PhCH₂-O⁺(H)R  ⟶ PhCH₂⁺ + HOR          Sₙ1 ionization of oxonium ion
  3. PhCH₂⁺ + I⁻       ⟶ PhCH₂-I                     Nucleophilic attack by I⁻  

If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:

ROH +HI ⟶ R-I + H-OH

Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).

The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).

4 0
4 years ago
0.5moles of monoalkanoic acid weighs 44g. determine the molecular formular​
Vlada [557]

Answer:

C4H8O2

Explanation:

Butanoic acid

C4H8O2

7 0
3 years ago
At what temperature does a gas at 1.00 atm and 20 degree Celsius have a pressure of 4.00 atm.
vfiekz [6]

Answer:

P1 =4 atm

T1= 20°C

P2=1 atm

T2=?

According to Gay-Lussac's Law or Third Gas Law,

P1T2=P2T1

4×T2=1×20

T2= 20/4

T2= 5°C

Answer At 5°C temperature does a gas at 1.00 atm !

7 0
3 years ago
The balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI is Pb(ClO3)2(aq)+2NaI(aq)⟶PbI2(s)+2NaClO3(aq) What
ryzh [129]

Answer : The mass of PbI_2 precipitate produced will be, 9.681 grams.

Explanation : Given,

Molarity of NaI = 0.210 M

Volume of solution = 0.2 L

Molar mass of PbI_2 = 461.01 g/mole

First we have to calculate the moles of NaI.

\text{Moles of }NaI=\text{Molarity of }NaI\times \text{Volume of solution}=0.210M\times 0.2L=0.042moles

Now we have to calculate the moles of PbI_2.

The balanced chemical reaction is,

Pb(ClO_3)_2(aq)+2NaI(aq)\rightarrow PbI_2(s)+2NaClO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaI react to give 1 mole of PbI_2

So, 0.042 moles of NaI react to give \frac{0.042}{2}=0.021 moles of PbI_2

Now we have to calculate the mass of PbI_2.

\text{Mass of }PbI_2=\text{Moles of }PbI_2\times \text{Molar mass of }PbI_2

\text{Mass of }PbI_2=(0.021mole)\times (461.01g/mole)=9.681g

Therefore, the mass of PbI_2 precipitate produced will be, 9.681 grams.

6 0
4 years ago
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