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2 years ago

5

The price of A cup of coffee was $2.20 yesterday today the price rose to $2.55 find the percentage increase round your answer to

the nearest 10th of a percent

1 answer:

Anna11 [10]2 years ago

4 0

.35 is the raise of the cup of coffee

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Talia spent 3/4 of this week's allowance on candy. Of the money she spent on candy, 5/6 was spent on gummy bears. What fraction

Anna71 [15]

<span>Tabia spent 15/24 of this week's allowance on gummy bears. She can calculate that by multiplying 3/4 times 5/6. To do that, she multiplies the top numbers of each fraction together (3 times 5 equals 15), and to get the top number of the fraction. Then she multiplies the bottom numbers together (4 times 6 equals 24) to get the bottom number.</span>

3 0

3 years ago

HELP I HAVE TO FINISH THIS FAST

Usimov [2.4K]

Answer:

13 minus 3x cubed

Step-by-step explanation:

6 0

3 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

2 years ago

Write an equation in slope-intercept form for each graph shown.<br><br><br> Please help!!!!!!!

stiv31 [10]

Answer:

y = 2x-3

Step-by-step explanation:

We have 2 points so we can find the slope

m = (y2-y1)/(x2-x1)

= (1--3)/(2-0)

= (1+3)/(2-0)

=4/2

= 2

The y intercept (where x=0) is -3

We can use the slope intercept form of the equation

y= mx+b where m is the slope and b is the y intercept

y = 2x-3

3 0

3 years ago

Read 2 more answers

Michael lives in the northwest corner of Clark County. Clara

timama [110]

Answer:

About 0.41 hours

Step-by-step explanation:

THe distance between Michael and Clara is 44 km.

We know D = RT,

Where

D is distance

R is rate (speed)

T is time

For Michael, we can write:

D = 47t

For Clara, we can write:

D = 61t

If we let michael's distance be x, Clara's distance would be 44 - x

So, we can say:

x = 47t

and

44 - x = 61t

Putting first equation into 2nd, we get:

44 - 47t = 61t

SOlving:

44 - 47t = 61t

44 = 61t + 47t

44 = 108t

t = 44/108 = 0.41 hours

The commute took 0.41 hours

7 0

2 years ago