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tester [92]
3 years ago
10

David bought 4.75 pounds of chicken for $11.40. How much did he pay per pound?

Mathematics
2 answers:
Luden [163]3 years ago
6 0
David payed $2.40 per pound
Genrish500 [490]3 years ago
4 0
He paid 2.40 per pound
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3x-7y=6<br> 2x+7y=4<br> Solve by elimination
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3 years ago
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Pls help f(x)=2(x+1)^2+3
lidiya [134]

Answer:

y= 2x² + 2x +3

Step-by-step explanation:

y=f(x)

y=2( x^2 + 1^2 +2(x)(1) ) + 3

y=2x^2 + 1 + 2x +3

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3 years ago
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Find all points having an x-coordinate of 5 whose distance from the point (2, 6) is 5
galina1969 [7]

Answer:

(5,2) and (5,10)

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

points\ (2,6),(5,y)\\d=5

substitute in the formula

5=\sqrt{(y-6)^{2}+(5-2)^{2}}

solve for y

5=\sqrt{(y-6)^{2}+(3)^{2}}

5=\sqrt{(y-6)^{2}+9}

square both sides

25=(y-6)^{2}+9

(y-6)^{2}=25-9

(y-6)^{2}=16

square root both sides

y-6=\pm4

y=6\pm4

y=6+4=10

y=6-4=2

therefore

The points are

(5,2) and (5,10)

6 0
3 years ago
What is the slope of the line that passes through the points (8,-8) and (5,-1)?
dezoksy [38]

Hey there!

  • Answer :

\sf{ \purple{ \boxed{\bold{m =  -  \dfrac{7}{3} }}}}

\\

  • Explanation :

We are given the points \sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })} . To find the slope \sf{\purple{m}} of such a line, we use the slope formula which is the following:

\sf{ \purple{m} }=  \dfrac{\Delta y}{\Delta x}  =  \dfrac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}}

\\

⇢Now, by plugging in our values, we get :

\sf{ \purple{m}} =  \dfrac{ \red{ - 1} -  \orange{( - 8)}}{ \green{5} \:   -  \:  \blue{8}}  =  \dfrac{ \:  \: 7 \: }{ -  3 \: }  \\  \\  \implies \sf{ \purple{ \boxed{m =  -  \dfrac{7}{3} }}}

Therefore, the slope of the line is \sf{ \purple{ \boxed{m =  -  \dfrac{7}{3} }}}

8 0
2 years ago
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Equation of the circle is x^2 +(y-10)^2=16. The radius of the circle is___units. The center of the circle is at ___
lubasha [3.4K]

Answer:

Radius=4 units

Centre= (0,-10)

Step-by-step explanation:

Given equation of circle is x^2 +(y-10)^2=16

Comparing it with (x-h)^2 +(y-k)^2 = r^2 ,we get,

r=4

Since, centre of a circle=(h,k)=(0,-10)

8 0
2 years ago
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