Answer:
The answer is: 13 minutes
Step-by-step explanation:
First Let us form equations with the statements in the two scenario
Let the time in which the bell rings be 'x'
1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes
2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes
In both cases, the same distance is travelled, therefore, equation (1) = equation (2)
Next, collecting like terms:
dividing both sides by 3:
x = 390÷30 = 13
∴ x = 13 minutes
Answer:
Step-by-step explanation:
Answer:
2304
Step-by-step explanation:
8²×6² = ?
8² = 8×8 = 64
6² = 6×6 = 36
64×36 = 2304
Hoped this helped !
Cheers, Z
5000000+900000+2000+700+30+1
=5900000+2000+700+30+1
=5902000+700+30+1
=5902700+30+1
=5902730+1
=5902731
five million,
nine hundred two thousand, seven hundred thirty-one
(Word form)
Answer:
At x = 0, Sensitivity = Not defined
At x = 1, Sensitivity = 3.2974
At x = 2, Sensitivity = 2.71825
At x = 5, Sensitivity = 4.8729
At x = 10, Sensitivity = 29.6826
Step-by-step explanation:
We are given the following in the question:
where y is the output and x is the input of a system.
We define sensitivity as the ration of output to input.
At x = 0
At x = 1
At x = 2
At x = 5
At x = 10
