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mafiozo [28]
3 years ago
7

A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 9​% will need repairs​

twice, and 4​% will require three or more repairs. If you own two​ cars, what is the probability that ​a) neither will need​ repair? ​b) both will need​ repair? ​c) at least one car will need​ repair?
Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that a consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 9​% will need repairs​ twice, and 4​% will require three or more repairs.

No of cars -2

Each car is independent of the other.

Prob that a car does not need repair = 1-0.20-0.09-0.04 = 0.67

a) Prob (neither will need repair) =0.67*0.67=0.4489

b) Prob (both will need repair) =0.33*0.33=0.1089

c) Prob (atleast one will need repair) =1- neither repair

=1-0.4489

=0.5511

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