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mafiozo [28]
3 years ago
7

A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 9​% will need repairs​

twice, and 4​% will require three or more repairs. If you own two​ cars, what is the probability that ​a) neither will need​ repair? ​b) both will need​ repair? ​c) at least one car will need​ repair?
Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that a consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 9​% will need repairs​ twice, and 4​% will require three or more repairs.

No of cars -2

Each car is independent of the other.

Prob that a car does not need repair = 1-0.20-0.09-0.04 = 0.67

a) Prob (neither will need repair) =0.67*0.67=0.4489

b) Prob (both will need repair) =0.33*0.33=0.1089

c) Prob (atleast one will need repair) =1- neither repair

=1-0.4489

=0.5511

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Answer:

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Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

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Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)

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