3 years ago

What is the general form of the equation of the given circle with center A

1 answer:

5 0

When the centre A(xa,ya) and radius are given, the general equation is

(x-xa)^2+(y-ya)^2=r^2

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Ronch [10]

Answer: $6 + 2 (x+4)$ = $\frac{3}{2}$ $(3-x)$

Step-by-step explanation:

let the number be x , then :

six added to twice the sum of a number and four means :

$6 + 2 (x+4)$

one half of the difference of three and the number means :

$\frac{3}{2}$ $(3-x)$

combining the two , we have

$6 + 2 (x+4)$ = $\frac{3}{2}$ $(3-x)$

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Step-by-step explanation:

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