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Igoryamba
3 years ago
7

What is the general form of the equation of the given circle with center A

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0
When the centre A(xa,ya) and radius are given, the general equation is

(x-xa)^2+(y-ya)^2=r^2

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I really need help asap show all work​
Triss [41]

Note: Consider we need to find the factor form of the given expression by taking out the GCF.

Given:

The expression is:

-42k^3+24k^4+12k^5

To find:

The factor form of the given expression.

Solution:

We have,

-42k^3+24k^4+12k^5

It can be written as:

=6k^3(-7)+6k^3(4k)+6k^3(2k^2)

Taking out the greatest common factor (GCF), we get

=6k^3(-7+4k+2k^2)

Therefore, the factor form of the given expression is 6k^3(-7+4k+2k^2).

8 0
3 years ago
#7:Write the expression in simplest<br> radical form.<br> V24x5y2
vazorg [7]

2x^2y√6x


the image has the answer in a mor clear form


8 0
2 years ago
1: n/-3 - 8 &lt; 17<br> 2: n/-2 + 11 &gt; 17
cupoosta [38]

Answer:

1: n > -75

2: n < -12

Step-by-step explanation:

1: n/-3 - 8 < 17

n/-3 (- 8 + 8) < 17 + 8

n/-3 < 25

n/-3(-3) < 25(-3)

n < -75

n > -75 (switch symbol when you divide or multiply by a negative number)

2: n/-2 + 11 > 17

n/-2 (+ 11 - 11) > 17 - 11

n/-2 > 6

n/-2(-2) > 6(-2)

n > -12

n < -12 (switch symbol when you divide or multiply by a negative number)

7 0
2 years ago
Help me asap
sasho [114]

Answer:

6p =120

Step-by-step explanation:

well the p's are very close together in a sense that we are going to multiply instead of add because they the p's would have space in between

6 * 20 = 120

so p= 20

6 0
3 years ago
Read 2 more answers
Ishaan is 3 times as old as Chris and is also 14 years older than Chris. How old is ishaan?
hram777 [196]

Answer:We are also given that Ishaan is 14 years older than Christopher, so I is also 14 more than c. This gives that I = c + 14. Since I = 3c and I = c + 14, we have that 3c is equal to c + 14, giving the equation 3c = c + 14.

well this is from google and just so u know the letters stand for the names

8 0
3 years ago
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