Write a question about something else you would like to learn about extremophiles.

a clear liquid is poured into a beaker containing another clear liquid. A cloudy yellow substance forms, as if out of nowhere, b

konstantin123 [22]

A precipitate forms from a double displacement reaction or metathesis.

Explanation:

If given two clear solutions and upon reacting a cloudy/insoluble substance forms with the rest of the liquid being clear, a double displacement reaction has been carried out. The insoluble cloudy substance is called precipitate.

the driving force for the bulk of double displacement reactions is the formation of precipitates.
from careful observations, a solubility chart has been developed. If the compounds reacting are known, using the chart, a chemist can predict whether a precipitate will form or not.

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8 0

3 years ago

A sample of gas has an initial volume of 20 L and an initial pressure of 2.5 atm. If the pressure changes to 3.1 atm, what is th

Studentka2010 [4]

The new volume is mathematically given as

V2= 16.12 L

<h3>What is the new volume?</h3>

Question Parameters:

A sample of gas has an initial volume of 20 L

and an initial pressure of 2.5 atm.

If the pressure changes to 3.1 atm

Generally, the equation for Pressure is mathematically given as

P1V1 = P2 V2

2.5 * 20 = 3.1 * V2

V2 = 50/3.1

V2= 16.12 L

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6 0

1 year ago

Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:

Sladkaya [172]

Answer:

Part A:

Charge is $P^{3-}$

Configuration is $1s^2 2s^22p^63s^23p^6$

Part B:

Charge is $Mg^{2+}$

Configuration is $1s^2 2s^22p^6$

Part C:

Charge is $Se^{2-}$

Configuration is $1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6$

Explanation:

Monatomic ions:

These ions consist of only one atom. If they have more than one atom then they are poly atomic ions.

Examples of Mono Atomic ions: $Na^+, Cl^-, Ca^2^+$

Part A:

For P:

Phosphorous (P) has 15 electrons so it require 3 more electrons to stabilize itself.

Charge is $P^{3-}$

Full ground-state electron configuration of the mono atomic ion:

$1s^2 2s^22p^63s^23p^6$

Part B:

For Mg:

Magnesium (Mg) has 12 electrons so it requires 2 electrons to lose to achieve stable configuration.

Charge is $Mg^{2+}$

Full ground-state electron configuration of the mono atomic ion:

$1s^2 2s^22p^6$

Part C:

For Se:

Selenium (Se) has 34 electrons and requires two electrons to be stable.

Charge is $Se^{2-}$

Full ground-state electron configuration of the mono atomic ion:

$1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6$

8 0

2 years ago

Why do we use a double arrow in the dissociation equation for a weak acid answer?

Zepler [3.9K]

Answer is: because weak acids do not dissociate completely.

The strength of an Arrhenius acid determines percentage of ionization of acid and the number of H⁺ ions formed. 
Strong acids completely ionize in water and give large amount ofhydrogen ions (H⁺), so we use only one arrow, because reaction goes in one direction and there no molecules of acid in solution.

For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).

Weak acid partially ionize in water and give only a few hydrogen ions (H⁺), in the solution there molecules of acid and ions.

For example cyanide acid: HCN(aq) ⇄ H⁺(aq) + CN⁻(aq).

4 0

2 years ago

slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.

pishuonlain [190]

Answer:

For A: The equation is $_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha$

For B: The equation is $_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha$

For C: The equation is $_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta$

Explanation:

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

$_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha$

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

For A: Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

$_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha$

For B: Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

$_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha$

For C: Thorium-239 emits a beta particle

The nuclear equation for this process follows:

$_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta$

6 0

2 years ago