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3 years ago

Identify the base in this acid-base reaction: NaOH + HCI --- NaCl + H,0

Chemistry

2 answers:

Stella [2.4K]3 years ago

6 0

Answer: NaOH

Explanation:

alina1380 [7]3 years ago

3 0

Answer:

NaOH would be the base

Explanation:

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A sample of neon gas in a bulb is at 149.05 °C and 349.84 kPa. If the pressure drops

KonstantinChe [14]

The new temperature (in °C) of the gas, given the data is –148.20 °C

<h3>Data obtained from the question </h3>

Initial temperature (T₁) = 149.05 °C = 149.05 + 273 = 422.05 K
Initial pressure (P₁) = 349.84 KPa
Volume = constant
New pressure (P₂) = 103.45 KPa
New temperature (T₂) =?

<h3>How to determine the new temperature </h3>

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since the volume is constant, we have:

P₁ / T₁ = P₂ / T₂

349.84 / 422.05 = 103.45 / T₂

Cross multiply

349.84 × T₂ = 103.45 × 422.05

Divide both side by 349.84

T₂ = (103.45 × 422.05) / 349.84

T₂ = 124.80 K

Subtract 273 from 124.80 K to express in degree celsius

T₂ = 124.80 – 273

T₂ = –148.20 °C

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6 0

2 years ago

At 1 atm, how much energy is required to heat 39.0 g of h2o(s at –24.0 °c to h2o(g at 121.0 °c?

earnstyle [38]

Q = mcΔt, q = energy [J] m = mass (of water) [g]; c = specific heat capacity of water [J g⁻¹ K⁻¹/°C⁻¹]; Δt = change in temperature [K/°C]
Δt = 121 - -24 = 145
q = 39 × 4.18 × 145
q = 23637.9 J

4 0

3 years ago

six different aqueous solutions are represented in the beakers below, and there total volumes are noted. (a) which solution has

wolverine [178]

The molarity of the solutions are as follows:

solution B has the highest molarity
solutions A, D and F have the same molarity
solutions A and C are mixed together have a lower molarity than B
solution F and D will have the same molarity
Volume of water required to be evaporated is 8.3 mL

<h3>What is molarity of a solution?</h3>

The molarity of a solution is the amount in moles of a substance present in a given volume of solution.

From the image of the solution given:

solution B has the highest molarity
solutions A, D and F have the same molarity
when solutions A and C are mixed, the resulting solution have a lower molarity than B
solution F and D will have the same molarity after 75 mL and 50 mL of water are added to each respectively
the molarity of B is 12/50 = 4/16.7. Volume of water required to be evaporated = 25 - 16.7 = 8.3 mL

Therefore, the molarity of the solutions depends on the moles of substance present per given volume of solution.

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6 0

2 years ago

Which chemical equation represents a synthesis reaction?A.HCl + LiOH → LiCl + H2OB.2Na + MgCl2 → 2NaCl + Mg.H2CO3 → H2O + CO2D.C

Zina [86]

Answer:

Explanation:

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6 0

3 years ago

How many grams of nan3 are required to produce 19.0 ft3 of nitrogen gas, about the size of an automotive air bag, if the gas has

Papessa [141]

The balanced chemical reaction is given as:

$2NaN_{3}(s)\rightarrow 2Na(s)+3N_{2}(g)$

Now, convert $19.0 ft^{3}$ into litres.

$1 ft^{3} = 28.3168$

So, $19.0 ft^{3} = 19\times 28.3168 = 538.0192 L$

Density is equal to the ratio of mass to the volume.

$D=\frac{M}{V}$

where, M = mass and V= volume $(538.0192 L)$

Substitute the value of density and volume in formula to get the value of mass.

$1.25 g/L=\frac{M}{538.0192 L}$

$1.25 g/L\times 538.0192 L= M$

$Mass = 672.524 g$

Now, number of moles of $N_{2}$ gas= $\frac{672.524 g}{28.02 g/mol}$

= $24.00 moles$

According to the reaction, 2 moles of sodium azide gives 3 moles of nitrogen gas.

Now, in 24.00 moles of nitrogen gas produced from= $\frac{2 moles of sodium azide}{3 moles of nitrogen gas}\times 24.00 moles$ of nitrogen gas, moles of sodium azide.

number of moles of sodium azide = $16 moles$

Mass of sodium azide in g = $number of moles\times molar mass of sodium azide$ .

= $16 moles\times 65.00 g/mol$

= $1040 g$

Thus, mass of sodium azide which is required to produce $19.0 ft^{3}$ of nitrogen gas = $1040 g$

3 0

3 years ago