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Evgen [1.6K]
3 years ago
7

Bao + ........ --> BaCO3 + ......

Chemistry
1 answer:
scoray [572]3 years ago
6 0

Explanation:

Bao + .....Co2... --> BaCO3 + ......

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Do you guys have an answer?
padilas [110]

Answer:

5095

Explanation:

7 0
2 years ago
Read 2 more answers
alculate the energy for vacancy formation in silver, given that the equilibrium number of vacancies at 800°C (1073 K) is 3.6 × 1
bearhunter [10]

The answer & explanation for this question is given in the attachment below.

4 0
3 years ago
Calcium carbonate forms limestone, one of the most common rocks on Earth. It also forms stalactites, stalagmites, and many other
max2010maxim [7]

Answer:  CaCO_3(s)\rightarrow CaO(s)+CO_2(g) , 0.533 L

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

According to avogadro's law, 1 mole of every substance occupies 22.4 L of volume at STP.

Number of moles =\frac{\text {given mass}}{\text {Molar mass}}

moles of calcium carbonate = \frac{2.38g}{100g/mol}=0.0238mol

As 1 mole of calcium carbonate produces = 22.4 L of carbon dioxide at STP

Thus 0.0238 moles of calcium carbonate produces =\frac{22.4 L}{1}\times 0.0238=0.533L of carbon dioxide at STP

3 0
3 years ago
The population size of a predator species is directly controlled by _____. the population cycle of parasites the population cycl
AVprozaik [17]
The population size of its prey 

6 0
3 years ago
Read 2 more answers
Na+CL2=2NACL is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant
Elina [12.6K]

Excess reactant : Na

NaCl produced : = 16.497 g

<h3>Further explanation</h3>

Given

Reaction(balanced)

2Na + Cl₂⇒ 2NaCl

20 g Na

10 g Cl₂

Required

Excess reactant

NaCl produced

Solution

mol Na(Ar = 23 g/mol) :

= 20 : 23 = 0.87

mol Cl₂(MW=71 g/mol):

= 10 : 71 g/mol = 0.141

mol : coefficient :

Na = 0.87 : 2 = 0.435

Cl₂ = 0.141 : 1 = 0.141

Limiting reactant : Cl₂(smaller ratio)

Excess reactant : Na

Mol NaCl based on mol Cl₂, so mol NaCl :

= 2/1 x mol Cl₂

= 2/1 x 0.141

= 0.282

Mass NaCl :

= 0.282 x 58.5 g/mol

= 16.497 g

4 0
3 years ago
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