This one is easy. It's just addition and subtraction. Add the partial pressure of Argon and the partial pressure of Helium:
152 kPa
<u>+305 kPa</u><u>
</u> 457 kPa
Next, subtract the result from the total pressure:
1015 kPa
<u>- 457 kPa</u>
558 kPa
Answer:
The answer is
<h2>1, 214, 285.71 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass of gas = 8.5 × 10^9 g
But 1 L = 1000 mL
So 7 L = 7000 mL
volume = 7000 mL
So the density of the gas is

We have the final answer as
1, 214, 285.71 g/mL
Hope this helps you
This is an incomplete question, here is a complete question.
Ethanol has a heat of vaporization of 38.56 kJ/mol and a normal boiling point of 78.4 °C. What is the vapor pressure of ethanol at 14 °C?
Answer : The vapor pressure of ethanol at
is 
Explanation :
The Clausius- Clapeyron equation is :

where,
= vapor pressure of ethanol at
= ?
= vapor pressure of ethanol at normal boiling point = 1 atm
= temperature of ethanol = 
= normal boiling point of ethanol = 
= heat of vaporization = 38.56 kJ/mole = 38560 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:


Hence, the vapor pressure of ethanol at
is 