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victus00 [196]
3 years ago
13

Anyone who can do this please give me the right graph I would appreciate it

Mathematics
2 answers:
Svetllana [295]3 years ago
5 0
Are graph b and c the same ?
igor_vitrenko [27]3 years ago
3 0
Graph c
I think is the answer don’t blame me if I got it wrong
I hope this helps
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I don’t understand anything someone please help me :/
Artist 52 [7]

Answer:

answer choice c=6

Step-by-step explanation:

since the question says that round to the nearest

mile then you would round 5.7 to get you 6 so

your answer is 6

Hope this help you :))

 please give me branliest.                                                              

8 0
3 years ago
Yen had 19 songs on his mp3 player. he downloaded 9 more songs today, and then he decided to split them all equally among 4 play
ella [17]
7 songs in each playlist

3 0
3 years ago
Use Cramers Rule to solve the system <br> 2x - 3y = 11<br> -6x + 8y = 34
Nastasia [14]

Step-by-step explanation:

given :

2x - 3y = 11

-6x + 8y = 34

find : the solutions of the system by using Cramers Rule.

solutions:

in the matrix 2x2 form =>

[ 2 -3] [x] [11]

=

[-6 8] [ y] [34]

D =

| 2 -3 |

|-6 8 |

= 8×2 - (-3) (-6)

= 16-18 = -2

Dx = | 11 -3 |

| 34 8 |

= 11×8 - (-3) (34)

= 88 + 102

= 190

Dy = | 2 11 |

|-6 34 |

= 2×34 - (-6) (11)

= 68 + 66

= 134

x = Dx/D = 190/-2 = -95

y = Dy/D = 134/-2 = -67

the solutions = {-95, -67}

8 0
3 years ago
Read 2 more answers
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
Solve the equation 0.4+0.5=-4.7-0.6z
Charra [1.4K]
0.9 = -4.7 - 0.6z
0.9 + 4.7 = -0.6z
5.6 = -0.6z
z = 5.6 ÷ -0.6
z = -9.33
7 0
3 years ago
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