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2 years ago

Find the shaded AREA

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

8 0

Answer:

26 sq. in

Step-by-step explanation:

Area of the shaded region = Total area of the figure - Area of the square inside.

The figure with dimensions 5 in. and 7 in. is a rectangle.

So, Area of the rectangle = 5 X 7 = 35 sq. in.

Area of the square inside = 3² = 9 sq. in.

Therefore, Area of the Shaded figure = 35 - 9 = 26 sq. in.

Hence, the answer.

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I'm very confused on how to solve this problem, can anyone please help? Thanks!

Pepsi [2]

Answer:

Step-by-step explanation:

DC = 16 and

DB = 30 so

CB = 14

DB = 30 and

EB = 49 so

EB = 19

5 0

2 years ago

You are in a bike race. When you get to the first checkpoint, you are $\frac{2}{5}$

Black_prince [1.1K]

Answer:

The distance from the star to the second checkpoint is 4 miles

Step-by-step explanation:

The complete question in the attached figure

we know that

When you get to the second checkpoint, you are 1/4 of the distance to the finish

The distance from the star to the second checkpoint is equal to the total distance multiplied by 1/4

The total distance is 40 miles ( see the attached figure)

The distance from the star to the second checkpoint is

$\frac{1}{4}(40)=10\ miles$

<em>Find out the distance from the start to the first checkpoint</em>

Multiply the distance from the star to the second checkpoint by 2/5

$\frac{2}{5}(10)=4\ miles$

6 0

2 years ago

each year a tree grows 26 cm. after 4.5 years the tree is 292 cm. how tall was the tree when he moved into the house

jeka57 [31]

26×4=104
292-104=188
26÷2=13
188-13=175cm

the tree was 175cm when he moved in

7 0

2 years ago

The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each

ziro4ka [17]

Answer:

the length of the first side of the triangle is $\frac{28}{3}\ in$

the length of the second side of the triangle is $\frac{37}{3}\ in$

the length of the third side of the triangle is $\frac{19}{3}\ in$

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

we know that

$x=y-3$

$y=x+3$ -----> equation A

$x=z+3$

$z=x-3$ -----> equation B

The perimeter of the triangle is equal to

$P=x+y+z$

$P=28\ in$

$28=x+y+z$ -----> equation C

substitute equation A and equation B in equation C

$28=x+(x+3)+(x-3)$

solve for x

$28=3x$

$x=\frac{28}{3}\ in$

Find the value of each side

the first side of a triangle is x

$x=\frac{28}{3}\ in$

the second side of a triangle is y

$y=\frac{28}{3}+3=\frac{37}{3}\ in$

the third side of a triangle is z

$z=\frac{28}{3}-3=\frac{19}{3}\ in$

7 0

3 years ago

Find the LCD of the given rational equation: -3/x+2 + 5x/x-1 = x+2/x^2-3x+2

Natali [406]

Answer:

(x - 1)( x - 2) (x + 2) = x³ -x² -4x + 4.

Explanation:

1) Given equation:

3 5x x + 2
- ------- + -------- = ---------------
x + 2 x - 1 x² - 3x + 2

2) So, the denominators are x + 2, x - 1, and x² - 3x + 2

3) The LCD is the product of the common and non common factors raised to the greatest power.

4) x + 2, and x - 1 are already prime factors

5) Factor x² - 3x + 2

x² - 3x + 2 = (x - 2)(x - 1)

6) Then, the factors are x + 2, x - 1, and x - 2, and the LCD is the product of them:
(x - 1)( x - 2) (x + 2)

7) If you expand the products (distributive property) you get:
x³ -x² -4x + 4.

5 0

2 years ago

Find the shaded AREA​

Find the shaded AREA