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mario62 [17]
3 years ago
15

Helpp i am really bad with math

Mathematics
2 answers:
koban [17]3 years ago
8 0

Answer:

4y-12

Step-by-step explanation:

Multiply the outside number by the numbers in the bracket.

Example:4×y=4y Because y=1

4×3=12

2.Answer C

3(5x+1)

3×5x=15x

3×1=1

Which is equivalent to 3(5x+3)

Hope this helps.

Brut [27]3 years ago
7 0

Answer:

1. 4y-12

2. c

For #1 you distribute the 4 to the y and the 3. 4 times 3 equals 12.

For #2 you factor out the 3 and you get 3(5x+1)

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Describe a sequence of transformations that takes trapezoid A to trapezoid B
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Answer:

How do you describe the sequence of transformations?

Image result for Describe a sequence of transformations that takes trapezoid A to trapezoid B

When two or more transformations are combined to form a new transformation, the result is called a sequence of transformations, or a composition of transformations. Remember, that in a composition, one transformation produces an image upon which the other transformation is then performed.

Step-by-step explanation:

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3 years ago
( Brainliest and thanks! )<br> Solve for x
timurjin [86]

Answer:

22.5

Step-by-step explanation:

x+3x=90

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5 0
2 years ago
Read 2 more answers
Can someone tell me how
gulaghasi [49]

the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.

multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.

so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5   <----- notice, current coefficient times 3 divided by 4+1.

anyhow, with that out of the way, lemme proceed in this one.

\bf ~~~~~~~~\textit{binomial theorem expansion} \\\\ \qquad \qquad (1+ax)^n\implies \begin{array}{llll} term&coefficient&value\\ \cline{1-3}&\\ 1&+1&(1)^n(ax)^0\\\\ 2&+\frac{(1)(n)}{1}\to n&(1)^{n-1}(ax)^1\\\\ 3&+\frac{n\cdot (n-1)}{2}&(1)^{n-2}(ax)^2 \end{array}

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.

so then, we know that the expanded 2nd term is 24x therefore

\bf n(1)^{n-1}(ax)1 = 24x\implies n(1)(ax)=24x\implies nax=24x\implies n=\cfrac{24}{a}

we also know that the expanded 3rd term is 240x², therefore we can say that

\bf \cfrac{n(n-1)}{2}~~(1)^{n-2}(ax)^2 = 240x^2\implies \cfrac{n(n-1)}{2}(1)(a^2x^2) = 240x^2 \\\\\\ \cfrac{(n^2-n)(a^2x^2)}{2}=240x^2\implies \cfrac{(n^2-n)(a^2)}{2}=\cfrac{240x^2}{x^2}\implies \cfrac{a^2n^2-a^2n}{2}=240 \\\\\\ a^2n^2-a^2n=480

but but but, we know what "n" equals to, recall above, so let's do some quick substitution

\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft

7 0
3 years ago
Which function is represented by the graph
nexus9112 [7]

Answer:

the 3rd one

Step-by-step explanation:

6 0
4 years ago
2) Why is it that when you fill the venn diagram with the number of elements, you
larisa86 [58]

Answer:

This is because it is easier this way.

You avoid the problem of putting an element in one set and then realizing that the element also belongs to another set, then you must erase something in order to put the element in both sets. Starting with the intersection allows you to know where will be each set in the diagram, and in this way, the diagram should end up being more readable or "clean".

This may seem small, but being "clean" when doing math, will allow you to have an easier time dealing with a lot of problems. And also will be easier for other people when reading your equations and such.

6 0
4 years ago
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