Answer:
The new height of the water is 6.167 m
Step-by-step explanation:
The volume of the pool is given by the product of it's three dimensions width, length and height. In the initial situation we have a pool with width equals 4m, the length equals 6m and height of the water of 2m. So we can find the volume as seen bellow:
initial volume = length*width*height = 6*4*2 = 48 m^3
Then 100 m^3 were added to the pool, so it's new volume will be the sum of the initial volume and the added water so we have:
final volume = initial volume + 100 = 48 + 100 = 148 m^3
Since the only dimension that can change in this situation is the height ofthe water we can use the formula for the volume to find the new height, as seen below:
final volume = length*width*(new height)
148 = 6*4*(new height)
6*4*(new height) = 148
24*(new height) = 148
new height = 148/24 = 6.167 m
The new height of the water is 6.167 m
The gradient of the tangent to the curve y = 5x³ + 3x² - x + 4 is 15x²+6x-1.
<h3>What is the gradient?</h3>
A differential operator is used for a function having a vector value in three dimensions to produce a vector whose three components are the partial derivatives of the function with respect to its three variables.
The given equation for the curve is;
y = 5x³ + 3x² - x + 4
The gradient of the tangent to the curve is;
Hence,the gradient of the tangent to the curve y = 5x³ + 3x² - x + 4 is 15x²+6x-1.
To learn more about the gradient refer to;
brainly.com/question/13020257
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146=2(l)+2(w) Let 4w-7=l
146=2(4w-7)+2w
146=10w-14 Add 14 to both sides
160=10w Divide by 10
16=Width Plug width back into the formula
57=Length
