Answer:
Volume of ammonia produced = 398.7 dm³
Explanation:
Given data:
Volume of N₂ = 200 dm³
Pressure and temperature = standard
Volume of ammonia produced = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of N₂:
PV = nRT
1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K
n = 200 atm.L /22.41 atm.L/mol
n = 8.9 mol
Now we will compare the moles of ammonia and nitrogen.
N₂ : NH₃
1 : 2
8.9 : 2/1×8.9 = 17.8 mol
Volume of ammonia:
1 mole of any gas occupy 22.4 dm³ volume
17.8 mol ×22.4 dm³/1 mol = 398.7 dm³
Answer : Oxidizing agent is
and Reducing agent is 
Explanation :
The given unbalanced redox reaction is,

In acidic medium, the balanced redox reaction is,

Oxidizing agent : Oxidizing agents are those agent which oxidizes other substance and itself get reduced.
Reducing agent : Reducing agents are those agent which reduces other substance and itself get oxidized.
In this redox reaction,
is an oxidizing agent and
is a reducing agent.
The redox reaction is also shown below.
The mass of a sample of substance with a volume of 60.5 ml and a density of 1.20g/ml is 72.6 g.
Density, denoted as ρ, is a physical property of a material which is defined as the ratio between mass and volume or mass per unit volume. It is a measure of how much "stuff" or compact an object has in a unit volume. The more dense a substance is, the heavier it feels for its size.
To find the density, use the formula given by:
ρ = 
where
ρ = density
m = mass
v = volume
Using the same formula, we can transform it to solve for mass, if the volume and density are given.
ρ = 
m = ρv
Putting the values in,
m = 1.20g/ml x 60.5 ml
m = 72.6 g
Hence, the mass of a sample of substance with a volume of 60.5 ml and a density of 1.20g/ml is 72.6 g.
To know more about density, visit brainly.com/question/6838128.
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Chemical formula:C3H8O
Flash point:53°F
Auto ignition temperature:455. 6°C
Solubility:Miscible with water, alcohol, ether, and chloroform
General characteristics:Colorless liquid with slight odor resembling that of rubbing alcohol