Answer:
The concentration of the HNO3 solution is 0.150 M
Explanation:
<u>Step 1:</u> Data given
Volume of the unknown HNO3 sample = 0.120 L
Volume of the 0.200 M Ba(OH)2 = 45.1 mL
<u>Step 2:</u> The balanced equation
2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O
<u>Step 3:</u> Calculate moles Ba(OH)2
moles Ba(OH)2 = molarity * volume
moles Ba(OH)2 = 0.200 M * 0.0451 L
moles Ba(OH)2 = 0.00902 moles
<u>Step 4:</u> Calculate moles of HNO3
For 1 mole of Ba(OH)2 we need 2 moles of HNO3
For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles
<u>Step 5</u>: Calculate molarity of HNO3
molarity = moles / volume
molarity = 0.01804 / 0.120 L
Molarity = 0.150 M HNO3
The concentration of the HNO3 solution is 0.150 M
