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olganol [36]
2 years ago
8

If a reaction ends with 5.5 grams of products, how many grams of reactants were required to start the reaction?

Chemistry
1 answer:
xz_007 [3.2K]2 years ago
5 0
5.5 grams of reactants. According to the Law of Conservation of Mass, mass isn’t created or lost through any chemical changes, so the total mass should remain constant from the initial reactants to the final products.
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Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

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2 years ago
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3 years ago
The photo shows nervous tissue.
Nikolay [14]

Answer:

The answer is c( to send signals to control the body)

7 0
3 years ago
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Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of CO2
Vlada [557]
To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:

r1/r2 = √(m2/m1)    

where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol) 

r1 = 1.6r2

1.6 = √(44.01 / m1)
m1 = 17.19 g/mol
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2 years ago
Why are plant oils important in our diet?
Lesechka [4]
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Vegetable oil or plant oil are healthier compare to the other oil. It also lessen the unwanted and unhealthy fats of an oil and gives only proper health diet to our body.</span>



6 0
3 years ago
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