Question

A 20 kg metal bar made of tin and silver lost 2 kg of its weight in the water. If 10 kg of tin loses 1.375 kg in the water and 5 kg of silver loses 0.375 kg, what is the ratio of tin to silver in the bar?

Answer 1

Answer:

Ratio of tin to silver in the bar is 2:3      

Step-by-step explanation:

We are given the following in the question:

10 kg of tin loses 1.375 kg in the water

Percentage of weight lost by tin  =

$\dfrac{1.375}{10}\times 100\% = 13.75\%$

5 kg of silver loses 0.375 kg

Percentage of weight lost by silver =

$\dfrac{0.375}{5}\times 100\% = 7.5\%$

20 kg bar loose 2 kg in water.

Percentage of weight lost by metal =

$\dfrac{2}{20}\times 100\% = 10\%$

Let x be the amount of tin and y be the amount of silver in bar.

Thus, we can find the ratio as:

$\dfrac{x}{y} = \dfrac{\text{Silver's loss - Average loss}}{\text{Average loss - Tin's loss}}\\\\\dfrac{x}{y} = \dfrac{7.5-10}{10-13.75} = \dfrac{2}{3}$

is the required ratio.