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Rzqust [24]
2 years ago
12

A reaction at −8.0°C evolves 854.mmol of boron trifluoride gas. Calculate the volume of boron trifluoride gas that is collected.

You can assume the pressure in the room is exactly 1atm. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Bas_tet [7]2 years ago
5 0

Answer:  The volume of boron trifluoride gas that is collected is 18.6 L

Explanation:

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 1 atm

V= Volume of the gas= ?

T= Temperature of the gas in kelvin =-8.0^0C=273+(-8.0)=265K

R= Gas constant = 0.0821Latm/Kmol

n=  moles of gas=  854 mmol = 0.854 mol   (1mmol=0.001mol)

1atm\times V=0.854\times 0.0821\times 265

V=18.6L

Thus volume of boron trifluoride gas that is collected is 18.6 L

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3 years ago
In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t
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4.81 moles

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Pressure at which gauge reads zero = 14.7 psi

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The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

68.2297 atm × 1.5 L = n × 0.0821 L.atm/K.mol × 298.15 K  

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4 0
3 years ago
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Answer:

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Boiling a liquid result in a gas

7 0
2 years ago
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