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Elena L [17]
3 years ago
8

A sleeping 68 kg man has a metabolic power of 65 w . you may want to review ( pages 323 - 327) . part a how many calories does h

e burn during an 8.0 hour sleep
Chemistry
1 answer:
Kazeer [188]3 years ago
8 0

<u>Given:</u>

Mass = 68 kg

Power = 65 W

<u>To determine:</u>

Calories burned during an 8.0 hr sleep

<u>Explanation:</u>

Energy is expressed as:

Energy = Power * Time

Now, the unit of power = Watt (W)

1 W = 1 J/s i.e. 65 W = 65 J/s

Time = 8 hrs = 8 * 3600 s = 28800 s

Energy = 65 J/s * 28800 s = 1872000 J

Convert Joules (J) to calories (cal)

1 cal = 4.184 J

The calculated energy = 187200 J * 1 cal/4.184 = 447418 cal

Ans: The man burns nearly 447.4 kcal during an 8 hr sleep




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For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

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3 years ago
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Explanation:

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2 years ago
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1 sulfide

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Explanation:

8 0
2 years ago
How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g
SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

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ppm of Lead = \frac{Lead}{Water} \times 10^6 = \frac{1.30}{250} \times 10^6 = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0
3 years ago
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