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AVprozaik [17]
3 years ago
6

In science, a summary of observed behavior is referred to as a(n)

Chemistry
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

Law

Explanation:

A law is a summary of observed (measurable) behavior, whereas a theory is an explanation of behavior. A law tells what happens; a theory (model) is our attempt to explain why it happens.

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In a car engine gasoline is burning to create mechanical energy which of the following statements is true? A. Some energy is los
Anvisha [2.4K]

Answer:

Some energy is lost as heat

Explanation:

It is correct to say that as the gasoline is converted to mechanical energy in the automobile engine, some of the energy is lost as heat.

Heat energy is on of the ways energy is lost in any system. The movement of mechanical parts and even the combustion of the gasoline produces heat energy.

These energy are usually lost to the environment.

4 0
3 years ago
Which formula represents copper(I) oxide?<br> (1) CuO (3) Cu2O<br> (2) CuO2 (4) Cu2O2
faust18 [17]
The answer is (3) Cu2O. Copper (I) has an oxidation state of +1 (that's what the "I" indicates). You can also think of this as copper (I) having a charge of +1. Oxygen has an oxidation state of -2 (that's just a rule you have to know), and you can think of it as oxygen having a charge of -2. You need oxidation numbers in a neutral compound to add up to 0 (or charges in a neutral compond to add up to 0), so you need two Cu to balance the O, which is Cu2O.
3 0
3 years ago
Read 2 more answers
What is the total volume of solution that was dispensed from this burette? before <br><br> after
monitta
Yeah answer should be .6 ml
6 0
3 years ago
Read 2 more answers
assume you have a 500 g sample of a radioactive isotope with a half-life of 100 years. fill in the table showing how many grams
sweet-ann [11.9K]

Answer:

8.10 hours.

Explanation:

You start with 500.0g.

After the first half-life, you have 250.0g.

After the second, you have 125.0g.

After the third, you have 62.50g.

Therefore, it takes three half-lives to decay to 62.50g.

Therefore, the elapsed time must be triple the length of one half-life.

24.3

3

=

8.10

, so it is 8.10 hours.

Explanation:

3 0
3 years ago
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Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
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