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Tatiana [17]
3 years ago
15

Will bromine react with sodium

Chemistry
1 answer:
denis-greek [22]3 years ago
4 0
Yes. bromine and sodium iodide can react to form sodium bromine and free iodine
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Which of the following systems in not directly involved in the body's regulation of water?
s344n2d4d5 [400]

The muscular system is the only system that does not directly involved in the body's regulation of water. So lettered B is the answer.

Have a good day!

7 0
3 years ago
7.32 moles of hydrogen reacts with 48.97 grams of nitrogen, how many moles of ammonia is produced?
faust18 [17]

3.5 moles of ammonia (NH₃) are produced

Explanation:

We have the following chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):

3 H₂ + N₂ → 2 NH₃

number of moles = mass / molecular weight

number of moles of N₂ = 48.97 / 28 = 1.75 moles

We see from the chemical reaction that 1 mole of N₂ will react with 3 moles of H₂, so 1.75 moles of nitrogen will react with 3 × 1.75 = 5.25 moles of H₂. We have 7.32 moles of H₂, a quantity more of what is needed, so the limiting reactant is N₂.

Knowing this we devise the following reasoning:

if         1 mole of N₂ produces 2 moles of NH₃

then   1.75 moles of N₂ produces X moles of NH₃

X = (1.75 × 2) / 1 = 3.5 moles of NH₃

Learn more about:

limiting reactant

brainly.com/question/7144022

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7 0
3 years ago
An electromagnet is magnetic because electric current runs through it<br> ОО<br> True<br> False
marshall27 [118]
That would be true :)
5 0
3 years ago
Read 2 more answers
How can a neutral atom become a positively-charged particle?
densk [106]
By getting ionised and losing electrons.
5 0
3 years ago
A sample of mercury has a mass of 607.0 lb and a volume of 0.717 ft. What is its specific gravity? Number SG= What are the units
stepan [7]

Answer:

Specific gravity of mercury is 13.56 and it is an unit-less quantity.

Explanation:

Mass of the mercury = m = 607.0 lb = 275330.344 g

1 lb = 453.592 g

Volume of the mercury  = v = 0.717 ft^3=20,303.18 mL

1 ft^3 = 28316.847 mL

Density of the mercury = d=\frac{m}{v}=\frac{275330.344  g}{20,303.18 mL}

d = 13.56 g/mL

Specific gravity of substance = Density of substance ÷ Density of water

S.G=\frac{d}{1 g/mL}

Specific gravity of mercury :

S.G=\frac{13.56 g/mL}{1 g/mL}=13.56 (unit-less quantity)

5 0
4 years ago
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