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Tatiana [17]
3 years ago
15

Will bromine react with sodium

Chemistry
1 answer:
denis-greek [22]3 years ago
4 0
Yes. bromine and sodium iodide can react to form sodium bromine and free iodine
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Calculate the molar mass of salicylic acid, c7h6o3.
gtnhenbr [62]
12×7+1×6+16×3=90+48=138
7 0
3 years ago
PLEASE ANSWERRRRRRRRR
ira [324]

Answer:

C. how the size of a magnet affects the strength of its magnetic pull on objects.

Explanation:

"Magnetic force" is <em>inversely proportional to distance squared. </em>This is also related to the size of a magnet. The bigger the size, the bigger the domain it occupies and the stronger the magnetic field. However, this is not often the case and it largely depends on the types of magnets.

In the situation above, Jazelle wanted to determine how her five different-sized magnet affect the strength of their magnetic pull on the paper clips. In order to do this, she tried to<em> measure the distance</em>. The<em> closer the distance</em>, the <em>higher the magnetic field</em> and the stronger the strength. The farther the distance, the<em> lower the magnetic field</em> and the <em>weaker the strength.</em>

So, this explains the answer.

3 0
3 years ago
How is the solubility of carbon dioxide gas in water increased?.answer.com?
olchik [2.2K]

Solubility of a gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. Solubility of a gas is inversely proportional to temperature.

So, the solubility of carbon dioxide gas in water is increased by increasing the partial pressure of carbon dioxide and by decreasing the temperature.

4 0
4 years ago
predict what will happen to the ammonia equilibrium system if hydrogen gas (H2) is added in the following reaction. N2(g) + 3H2(
labwork [276]

According to the <span>Le Chatelier's Principle, if a condition of system is changed, then the system try to become equilibrium again by correcting that change. 

N2(g) + 3H2(g) ⇄<span> 2NH3(g)

If H2(g) is added, then the concentration of H2(g) is high in the system. So the system tries to reduce it and become to equilibrium state. Hence to reduce that H2(g) the forward reaction is promoted. Then Concentration of product, NH3 gas is increased.</span></span>

4 0
3 years ago
Calculate the specific heat capacity of the unknown metal given the
Vedmedyk [2.9K]

Answer: The specific heat capacity of the unknown metal given is 0.466 J/g^{o}C.

Explanation:

Given: Mass = 225 g

Change in temperature = 13^{o}C

Heat energy = 1363 J

The formula used to calculate specific heat is as follows.

q = m \times C \times \Delta T

where,

q = heat energy

m = mass of substance

C = specific heat

\Delta T = change in temperature

Substitute the values into above formula as follows.

q = m \times C \times \Delta T\\1363 J = 225 g \times C \times 13^{o}C\\C = \frac{1363 J}{225 g \times 13^{o}C}\\= 0.466 J/g^{o}C

Thus, we can conclude that the specific heat capacity of the unknown metal given is 0.466 J/g^{o}C.

3 0
3 years ago
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